Ask question

Ask question

All categories

3 years ago

15

For a person who has a mass 60 kg , calculate the weight in Newton if 1 In equals 4.45 N , then what is the person's weight in p

ounds

1 answer:

wel3 years ago

4 0

Answer:

The answer to your question is a) 588.6 N b) 132.3 N

Step-by-step explanation:

Data

mass = 60 kg

weight = ?

Process

1.- Write the formula of weight

Weight = mass x gravity

gravity = 9.81 m/s²

2.- Substitution

Weight = 60 x 9.81

3.- Result

Weight = 588.6 kg m/s² = 588.6 N

4.- Convert Newtons to Pounds

1 pound ----------- 4.45 N

x ----------- 588.6 N

x = (588.6 x 1) / 4.45

x = 132.3 pounds

You might be interested in

Multiply 3.76 X.2<br> Show your work

WITCHER [35]

Answer:

7.52

Step-by-step explanation:

Write it out: 3.76 × 2
3.76 × 2 = 7.52

I hope this helps!

7 0

2 years ago

How many computers must the AB Computer Company sell to break even? Let x be the number of computers.

Eduardwww [97]

Answer:

The Company AB must sell 116 computers to break even

Step-by-step explanation:

we have

$R(x)=1.5x$ -----> equation A

$C(x)=145+\frac{1}{4}x$ ----> equation B

where

C is the cost function

R is the revenue function

x is the number of computers sold

we know that

Break even is when the cost is equal to the revenue

so

equate equation A and equation B

$1.5x=145+\frac{1}{4}x$

Solve for x

subtract 1/4x both sides

$1.5x-\frac{1}{4}x=145$

$1.5x-0.25x=145$

$1.25x=145$

Divide by 1.25 both sides

$x=116$

therefore

The Company AB must sell 116 computers to break even

7 0

2 years ago

Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method

antoniya [11.8K]

Answer:

a

The estimate is $- 0.0265\le K \le 0.0465$

b

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is $n_1 = 400$

The number of faulty breaks of method A is $X_1 = 32$

The number of microchips broken in method B is $n_2 = 400$

The number of faulty breaks of method A is $X_2 = 32$

The proportion of the faulty breaks to the total breaks in method A is

$p_1 = \frac{32}{400}$

$p_1 = 0.08$

The proportion of the faulty to the total breaks in method B is

$p_2 = \frac{28}{400}$

$p_2 = 0.07$

For this estimation the standard error is

$SE = \sqrt{ \frac{p_1 (1 - p_1)}{n_1} + \frac{p_2 (1- p_2 )}{n_2} } }$

substituting values

$SE = \sqrt{ \frac{0.08 (1 - 0.08)}{400} + \frac{0.07 (1- 0.07 )}{400} } }$

$SE = 0.0186$

The z-values of confidence coefficient of 0.95 from the z-table is

$z_{0.95} = 1.96$

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

$K = [p_1 - p_2 ] \pm z_{0.95} * SE$

substituting values

$K = [0.08 - 0.07 ] \pm 1.96 *0.0186$

$K = - 0.0265 \ or \ K = 0.0465$

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

$- 0.0265\le K \le 0.0465$

3 0

2 years ago

Find a solution to y3=117

sammy [17]

Answer:39

Step-by-step explanation:

y(3) = 117

3y/3 =117/3

y = 39

6 0

3 years ago

Read 2 more answers

I don't really understand this question

solmaris [256]

You just have to multiply 17.04 * 6.2 to get the answer. The answer is 105.648

6 0

2 years ago

Read 2 more answers