Split the second term in 9s^2 - 36s + 35 into two terms
9s^2 - 15s - 21s + 35
Factor out common terms in the first two terms, then in the last two terms
3s(3s - 5) - 7(3s - 5)
Factor out the common term 3s - 5
<u>(3s - 5)(3s - 7) </u>
To land on 0 the number would need to end with a .5 or .0 since that is the only way .0 can occur with counting down by.5( half)
Answer:
Step-by-step explanation:
Given;
x² - 2x - 1 = 0
Solve by completing the square method;
⇒ take the constant to the right hand side of the equation.
x² - 2x = 1
⇒ take half of coefficient of x = ¹/₂ x -2 = -1
⇒ square half of coefficient of x and add it to the both sides of the equation
⇒ take the square root of both sides;
Therefore, option B is the right solution.
Answer:
Step-by-step explanation:
5x + 13y = 232
12x + 7y = 218
For each choice:
a) The first equation can be multiplied by –13 and the second equation by 7 to eliminate y. So we have
- 65x - 169y = - 3016
84x + 49y = 1526
Can not eliminate x and y.
b) The first equation can be multiplied by 7 and the second equation by 13 to eliminate y. So we have
35x + 91 y = 1624
156x + 91y = 2834
Can not eliminate x and y if we ADD.
<em>(If we subtract, this is Yes)</em>
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c) The first equation can be multiplied by –12 and the second equation by 5 to eliminate x.
-60x - 156y = - 2784
60x + 35y = 1090
The answer is YES
d) The first equation can be multiplied by 5 and the second equation by 12 to eliminate x.
25x + 65y = 1160
144x + 84y = 2616
Can not eliminate x and y
The final answer is C
