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Alja [10]
3 years ago
15

What is the distance between A (-4,2) and B (12,4)

Mathematics
2 answers:
12345 [234]3 years ago
7 0
Your Answer is (4,3)
My name is Ann [436]3 years ago
3 0

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
A(\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\qquad
B(\stackrel{x_2}{12}~,~\stackrel{y_2}{4})\qquad \qquad
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
AB=\sqrt{[12-(-14)]^2+[4-2]^2}\implies AB=\sqrt{(12+14)^2+(4-2)^2}
\\\\\\
AB=\sqrt{26^2+2^2}\implies AB=\sqrt{680}

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Find the length x to the nearest whole number. A right triangle has a vertical leg of length x units, a base leg with a length o
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Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value of x is  x = 274 \ unites

Step-by-step explanation:

From the question we are told that

       The length of the vertical length is  x

      The length of the base leg is L = 330 + d units

      The length of the bisecting line segment is h

       The base angle is \theta  = 28^o

       The angle between d and line segment is  \theta_1 =  56^o

For the first angle

         Tan \theta_1 =  \frac{x}{d}

=>     d =  \frac{x}{Tan \theta _1}

 For the whole big triangle

      Tan \theta = \frac{x}{330 + d}

=>     d = \frac{x}{Tan \theta }  -330

So equating the both d

        \frac{x}{Tan \theta _1} =    \frac{x}{Tan \theta }  -330

Substitute values

        \frac{x}{Tan (56)} =    \frac{x}{Tan (28) }  -330

      0.6745 x =    1.880x  -330

       1.20549 x = 330

       x = 274 \ unites

     

   

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Step-by-step explanation:

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Step-by-step explanation:

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