Answer:
32°
Step-by-step explanation:
Given: 
∠DMQ = 58º
In this circle, the radius is DM. Since AD is tangent to the circle M, at point D, and the angle between a tangent and a radius is 90°
Therefore, ∠MDQ = 90°
The total angle in a triangle is 180°. Since we have the values of ∠MDQ and ∠DMQ, ∠DQM will be calculated as:
180 = ∠DMQ + ∠MDQ + ∠DQM
Solving for ∠DQM, we have:
∠DQM = 180 - ∠DMQ - ∠MDQ
∠DQM = 180 - 90 - 58
∠DQM = 32°
The measure of ∠DQM is 32°
 
        
             
        
        
        
The domain of a function f(x)/m(x) = 1/√x(x² - 4) is (0, ∞) - {0, 2, -2} for other function is shown in the solution.
<h3>What is a function?</h3>
It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
 
We have:
f(x) =  1/√x
m(x) = x² - 4
Domain of f(x)/m(x):
f(x)/m(x) = (1/√x)/(x² - 4)
f(x)/m(x) = 1/√x(x² - 4)
The denominator cannot be zero:
√x(x² - 4) ≠ 0
x(x - 2)(x+2) ≠ 0
x ≠ 0, 2, -2
and x > 0 
Domain of f(x)/m(x) is:   (0, ∞) - {0, 2, -2} or 
Domain of f(m(x)):
f(m(x)) = 1/√(x² - 4)
x² - 4 > 0
Domain: 
Domain of m(f(x)):
= ((1/√x)² - 4)
Domain: 
Thus, the domain of a function f(x)/m(x) = 1/√x(x² - 4) is (0, ∞) - {0, 2, -2} for other function is shown in the solution.
Learn more about the function here:
brainly.com/question/5245372
#SPJ1
 
        
             
        
        
        
Answer:
5{z}^{3}-222-9{z}^{2}5z
3
 −222−9z
2
Step-by-step explanation:
1 Collect like terms.
5{z}^{3}+(-224+2)-9{z}^{2}5z
3
 +(−224+2)−9z
2
  
2 Simplify.
5{z}^{3}-222-9{z}^{2}5z
3
 −222−9z
2
  
Done
 
        
             
        
        
        
Answer:
1440.08 mi
Step-by-step explanation:
Pythagorean Theorem:
 = 1440.08
 = 1440.08
 
        
             
        
        
        
Answer:
Step-by-step explanation:
A rectangle is shown with length x plus 10 and width 2 x plus 5.
so the rectangle area = length * width
= (x + 10) * (2x + 5)
an unshaded square with length x plus 1 and width x plus 1
so the unshaded square area = (x + 1) * (x + 1)
the shaded area = rectangle area - square area
= (x + 10) * (2x + 5) - (x + 1) * (x + 1)
= (2x^2 + 20x + 5x + 50) - (x^2 + x + x + 1)
= x^2 + 23x + 49