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morpeh [17]
3 years ago
15

Solve -6x+3y=9, -8x+4y=12 by elimination

Mathematics
1 answer:
Lerok [7]3 years ago
4 0
The answer is 678.09 plus 804
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\displaystyle\lim_{ x \rightarrow 0 } \left( \dfrac{ \sqrt[ m ]{ 1+αx \phantom{\tiny{!}}} \times \sqrt[ n ]{ 1+βx \phantom{\tiny
kramer

Answer:

What are you trying to ask.

Step-by-step explanation:

Please Write in a understandable  manner.

Thanks from India.

8 0
3 years ago
What is an equation in slope-intercept form of the line that passes through (6, −7)
Ber [7]

Answer:

y = -7/6x

Step-by-step explanation:

y - y1 = m*(x-x1)

m=y/x

y - (-7) = -7/6*(x-6)

y + 7 = -7/6x + 7

y = -7/6x + 7 - 7

y = -7/6

4 0
3 years ago
Find the missing side to the nearest tenth
Gre4nikov [31]

6.4 is the answer that is the answer

7 0
4 years ago
Read 2 more answers
What are like terms? How do you combine them? Can you give an example?
yan [13]
Like terms are when numbers with and without variables can be combined. ex: 4x+6-8x+=32
you would first combine 4x and -8x because they are the same.
6 0
3 years ago
Read 2 more answers
determine the equation of the circle if its center is (8,-6) and which passes through the points (5,-2).
ser-zykov [4K]

Answer:

(x - 8)² + (y + 6)² = 25

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

Here (h, k ) = (8, - 6 ) , then

(x - 8)² + (y - (- 6))² = r² , that is

(x - 8)² + (y + 6)² = r²

The radius is the distance from the centre to a point on the circle

Calculate r using the distance formula

r = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (8, - 6 ) and (x₂, y₂ ) = (5, - 2 )

r = \sqrt{(5-8)^2+(-2-(-6))^2}

  = \sqrt{(-3)^2+(-2+6)^2}

  = \sqrt{9+4^2}

  = \sqrt{9+16}

   = \sqrt{25}

   = 5

Then equation of circle is

(x - 8)² + (y + 6)² = 5² , that is

(x - 8)² + (y + 6)² = 25

6 0
2 years ago
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