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9966 [12]
3 years ago
13

3 + 2x -y =0 -3 -7y = 10x​

Mathematics
1 answer:
sweet [91]3 years ago
4 0

Answer:

(-1, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination
  • Solving systems of equations by graphing

Step-by-step explanation:

<u>Step 1: Define systems</u>

3 + 2x - y = 0

-3 - 7y = 10x

<u>Step 2: Rewrite systems</u>

3 + 2x - y = 0

  1. Add <em>y</em> to both sides:                    3 + 2x = y

<u>Step 3: Redefine systems</u>

y = 2x + 3

-3 - 7y = 10x

<u>Step 4: Solve for </u><em><u>x</u></em>

<em>Substitution</em>

  1. Substitute in <em>y</em>:                     -3 - 7(2x + 3) = 10x
  2. Distribute -7:                        -3 - 14x - 21 = 10x
  3. Combine like terms:            -14x - 24 = 10x
  4. Add 14x on both sides:        -24 = 24x
  5. Divide 24 on both sides:     -1 = x
  6. Rewrite:                                 x = -1

<u>Step 5: Solve for </u><em><u>y</u></em>

  1. Define original equation:                    -3 - 7y = 10x
  2. Substitute in <em>x</em>:                                     -3 - 7y = 10(-1)
  3. Multiply:                                                -3 - 7y = -10
  4. Add 3 to both sides:                            -7y = -7
  5. Divide -7 on both sides:                      y = 1

<u>Step 6: Graph</u>

<em>Check the solution set.</em>

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

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Let Y the random variable that represent the scores for the West population, and for this case we know the distribution for Y is given by:

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For this case we want this probability:

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And we can use the z score given by:

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And if we replace we got:

P(X \geq 125) = 1-P(X

Part b

For this case we need to define the following random variable R = X-Y and we know that the distribution of R is given by:

R \sim N (130-120= 10, \sigma_R = \sqrt{8^2 +10^2}=12.806)

And we want this probability:

P(R\geq 5)

We can use the z score given by:

z= \frac{R -\mu_R}{\sigma_R}

If we use this formula we got:

P(R \geq 5) = 1-P(R

Part c

For this case we select a sample size of n =3 for the Y distribution, the sample mean have the following distribution:

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And we want this probability:

P(\bar Y \geq 125) = P(Z> \frac{125-120}{5.774}) = 1-P(Z

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For this case we define the following random variable H = \bar X -\bar Y and the distribution for H is given by:

H \sim N (130-120=10, \sigma_H = \sqrt{\frac{8^2 +10^2}{3}}= 7.394)

And the z score would be given by:

z = \frac{H -\mu_H}{\sigma_H}

And if we find the probability required we got:

P(H\geq 5)= P(Z> \frac{5-10}{7.394}) = 1-P(Z

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