If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500
Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.
We have to find the probability of observing at least one car during any 5 minute time interval.
Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.
Probability during 20 minutes interval=609/625
Probability during 1 minute interval=609/625*20
=609/12500
Probability during 5 minute interval=(609/12500)*5
=609/2500
Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.
Learn more about probability at brainly.com/question/24756209
#SPJ4
Answer:
Lateral area =
pi * (radius) * √ [ height ^2 + radius^2 ] =
pi * ( 4 ) * √ [ 4^2 + 3^2 ] =
pi * ( 4 ) * √25 =
pi * ( 4 ) * (5 ) =
20 pi units^2 ≈ 62.8 units^2
Step-by-step explanation:
Answer:
2521.5
Step-by-step explanation:
20.5 · 10.25 · 12
2521.5
Answer:
Step-by-step explanation:
These triangles are similar triangles, so there is a number that you can multiply the sides of TUV to find the side lengths of QRS. looking at the triangle, the similar sides are RS being similar to UV and RQ being similar to UT.
If RS~UV, then there is a ratio between them. 54/36=1.5. The ratio is 1.5.
RQ~UT, and by a factor of 1.5, so divide RQ by the scale factor. 24/1.5=16. UT=16=x+5.
x+5=16, subtract 5 from both sides.
x=11
vertex = (3,- 5 )
given a quadratic in standard form : y = ax² + bx + c ( a ≠ 0 ), then
the x-coordinate of the vertex is
= - 
y = x² - 6x + 4 is in standard form
with a = 1, b = - 6 and c = 4, hence
= -
= 3
substitute this value into the equation for y- coordinate
y = 3² - 6(3) + 4 = 9 - 18 + 4 = - 5
vertex = (3, - 5 ) → second table