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Answer:
Perimeter of big rectangle = 38 units
Step-by-step explanation:
Let the sides of rectangle (1) = a and c cm
Sides of rectangle (2) = b and c cm
Sides of rectangle (3) = b and d cm
Sides of rectangle (4) = a and d cm
Perimeter of (1) = 2(length + width)
2(a + c) = 10
a + c = 5 ---------(1)
Perimeter of (2) = 2(b + c)
2(b + c) = 20
b + c = 10 -------(2)
Perimeter of (3) =2(b + d)
2(b + d) = 28
b + d = 14 --------(3)
Perimeter of (4) = 2(a + d)
2(a + d) = 18
a + d = 9 -------(4)
Since perimeter of the big rectangle = 2(a + b + c + d)
By adding equations (1) + (2) + (3) + (4),
(a + c) + (b + c) + (b + d) + (a + d) = 5 + 10 + 14 + 9
2(a + b + c + d) = 38
Therefore, perimeter of the rectangle ABCD = 38 units
