Answer:
x=0
Step-by-step explanation:
7/2x+6/4x=5/4x
7/2x=5/4x-6/4x
7/2x=-1/4x
7/2x-(-1/4x)=0
7/2x+1/4x=0
14/4x+1/4x=0
15/4x=0
x=0/(15/4)
x=0
Answer:
v=16/3
Step-by-step explanation:
3(2v-9)=5
Multiply 2v and -9 with 3
6v-27=5
Add 27 to both sides
6v=32
Divide both sides by 6
v=16/3
Answer:
Step-by-step explanation:
From your characteristic equation, your recursive equation is
the general solution:
The initial conditions are
For f(0) = 1, that is
For f(1) = 3, that is
From (*) and (**) you solve for A and B
you have A = 4/7 and B= 3/7
Replace A, B into the general one, you have the particular solution for the given condition
Answer:
In algebra, a quadratic equation (from the Latin quadratus for "square") is any equation that can be rearranged in standard form as ax^2+bx+c-0 where x represents an unknown, and a, b, and c represent known numbers, where a ≠ 0. If a .0, then the equation is linear, not quadratic, as there is no ax^2 term. The numbers a, b, and c are the coefficients of the equation and may be distinguished by calling them, respectively, the quadratic coefficient, the linear coefficient and the constant or free term.
Step-by-step explanation:
Good Question I just had a class about it 10 minutes ago such a coincidence! :)
Answer:
critical value is considered part of the rejection region.
Step-by-step explanation:
hope this helps!
