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Ierofanga [76]
3 years ago
12

Please help due todayyy://

Mathematics
1 answer:
Paul [167]3 years ago
4 0

Answer:

B. product graph

Step-by-step explanation:

Hope it helps

<em>C</em><em>a</em><em>r</em><em>r</em><em>y</em><em>O</em><em>n</em><em>L</em><em>e</em><em>a</em><em>r</em><em>n</em><em>i</em><em>n</em><em>g</em>

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What is the distance to the earth’s horizon from point P?<br><br> Express your answer as a decimal
rewona [7]

Answer:

The distance to the earth's horizon from point P is 216.2198187 mi, appriximately 216.22 mi

Step-by-step explanation:

This is a right triangle:

Hypotenuse: c=3959 mi + 5.9 mi → c=3964.9 mi

Leg 1: a=x=?

Leg 2: b=3959 mi

Using the Pytagorean theorem:

a^2+b^2=c^2

Replacing the known values:

(x)^2+(3959 mi)^2=(3964.9 mi)^2

Solving for x: Squaring:

x^2+15,673,681 mi^2=15,720,432.01 mi^2

Subtracting 15,673,681 mi^2 both sides of the equation:

x^2+15,673,681 mi^2-15,673,681 mi^2=15,720,432.01 mi^2-15,673,681 mi^2

x^2=46,751.01 mi^2

Square root both sides of the equation:

sqrt(x^2)=sqrt(46,751.01 mi^2)

x=216.2198187 mi

x=216.22 mi

3 0
3 years ago
Please help! I need help with this multiple choice question, thank you.
coldgirl [10]

Answer:

A. SAS B. SSS C. AAS D. ASA

Step-by-step explanation:

A: Line segments AE and EB are congruent and line segments CE and ED are also congruent. The Angles in between line segments AE and EB and line segments CE and ED are congruent to each other

B: Line segments QT and TS are congruent. Line segments QR and RS are congruent. Both triangles share line segment TR

C: Angles A and B are congruent. Angles D1 and D2 are congruent. Line segment CD is shared between both triangles.

D: Angles C1 and C2 are congruent. Angles B1 and B2 are congruent. Line segment CB is shared between the two triangles.

7 0
2 years ago
The rate at which a quantity of a radioactive substance decays is proportional to the quantity of the substance. The constant of
Butoxors [25]

Answer:

\frac{dN}{dt} = λN           N(0) = 6

N(t) = N₀e^(λt)

Applying the inital value condition

N(t) = 6e^(λt)

Step-by-step explanation:

Summarizing  the information briefly and stating the  variables in the problem.

t = time elapsed during the decay

N(t) = the amount of the radioactive substance remaining after time t

λ= The constant of proportionality  is called the decay constant or decay rate

Given the initial conditions

N(0) = N₀ = 6

The rate at which a quantity of a radioactive substance decays (\frac{dN}{dt}) is proportional to the quantity of the substance (N)  and λ is the constant of proportionality  is called the decay constant or decay rate :

\frac{dN}{dt} = λN          

N(t) = N₀e^(λt) ......equ 1

substituting the value of  N₀ = 6 into equation 1

N(t) = 6e^(λt)

3 0
3 years ago
What is -4(7x+5)=-160
puteri [66]

Answer is -23

Add 4 from both sides

Subtract 5 from both sides

Then divide 7

6 0
3 years ago
Read 2 more answers
Classify the quadrilateral, Explain your reasoning. Thank you!!
11111nata11111 [884]

Answer: y=7, x=2

Step-by-step explanation:

∠Q+∠P=180° (∠s between 2 // lines)

97°+(12y-1)°=180°

12y-1=83°

12y=84

y=7

5x+6=8x (Iso triangle)

x=2

8 0
2 years ago
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