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STatiana [176]
4 years ago
11

3. Consider the motion of the object whose velocity-time graph is given

Physics
1 answer:
notka56 [123]4 years ago
5 0

Answer:

16 m.

Explanation:

From the question given above, we obtained the following data:

Initial velocity (u) = 0 m/s

Final velocity (v) = 8 m/s

Initial time (t1) = 0 sec

Final time (t2) = 2 secs

Net Displacement (ΔD) =?

Velocity is defined as the rate of change of the displacement of an object with time. Mathematically, it is expressed as:

Change in velocity (Δv) = change in displacement (ΔD) / change in time (Δt)

Δv = ΔD / Δt

Next we shall determine the change in velocity and time. This is illustrated below below:

Initial velocity (u) = 0 m/s

Final velocity (v) = 8 m/s

Change in velocity (Δv) =?

Change in velocity (Δv) = v – u

Change in velocity (Δv) = 8 – 0

Change in velocity (Δv) = 8 m/s

Initial time (t1) = 0 sec

Final time (t2) = 2 secs

change in time (Δt) =?

change in time (Δt) = t2 – t1

change in time (Δt) = 2 – 0

change in time (Δt) = 2 secs.

Finally, we shall determine the net displacement of the object as follow:

Change in velocity (Δv) = 8 m/s

change in time (Δt) = 2 secs.

Net Displacement (ΔD) =?

Δv = ΔD / Δt

8 = ΔD/2

Cross multiply

ΔD = 8 × 2

ΔD = 16 m

Therefore, the net displacement of the object is 16 m.

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A ray diagram is shown. what does the letter x represent?
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Answer: Letter X in the diagram represent the angle of incidence

Explanation: One of the properties of wave is reflection. But before reflection can occur, there must have been a directed motion of wave particle towards a plane surface. The angle of incidence is the angle between the direction of motion of the wave particle ( for example; light) and the normal to the plane surface.

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4 years ago
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When the sound of source is moving away from the observer the observer will hear a
hammer [34]

a sound of lower fequency

6 0
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There is a person who throws a coin vertically downward with an initial speed of 11.8 m/s from the roof of a building, 34.0 m ab
omeli [17]

Answer:

Time taken by the coin to reach the ground is 1.69 s

Given:

Initial speed, v = 11.8 m/s

Height of the building, h = 34.0 m

Solution:

Now, from the third eqn of motion:

v'^{2} = v^{2} + 2gh

v'^{2} = 11.8^{2} + 2\times 9.8\times 34.0 = 805.64

v' = \sqrt{805.64} = 28.38 m/s

Now, time taken by the coin to reach the ground is given by eqn (1):

v' = v + gt

t = \frac{v' - v}{g} = \frac{28.38 - 11.8}{9.8} = 1.69 s

6 0
3 years ago
A roller-coaster car has a mass of 1240 kg when fully loaded with passengers. As the car passes over the top of a circular hill
LiRa [457]

Answer:

a)      N = 7.90 10³ N,  b) N = -1.04 10⁴ N

Explanation:

a) For this exercise we can use Newton's second law

             N -W = m (-a)

The relationship is centripetal, the negative sign of the acceleration is because it points towards the center of the circle

              a = v² / r

we substitute

             N = mg -m v² /r  

             N = m (g - v² /r)

let's calculate

v = 8.7 m / s

             N = 1240 (9.81 - 8.7²/22)

             N = 7.90 10³ N

b) v = 20 m / s

             N = 1240 (9.81 - 20²/22)

             N = -1.04 10⁴ N

8 0
3 years ago
During a circus act, an elderly performer thrills the crowd by catching a cannon ball shot at him. The cannon ball has a mass of
Phantasy [73]

Answer:

2.4681 m/s

Explanation:

m_1 = Mass of cannon ball = 29 kg

m_2 = Mass of performer = 65 kg

u_1 = Initial Velocity of cannon ball = 8 m/s

u_2 = Initial Velocity of performer = 0 m/s

v = Velocity of combined mass

As the linear momentum of the system conserved

m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow v=\frac{m_1u_1 + m_2u_2}{m_1 + m_2}\\\Rightarrow v=\frac{29\times 8 + 65\times 0}{29 + 65}\\\Rightarrow v=2.4681\ m/s

The recoil velocity is 2.4681 m/s

3 0
3 years ago
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