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SIZIF [17.4K]
3 years ago
13

What does this meannn plsssssss

Physics
2 answers:
VARVARA [1.3K]3 years ago
6 0

Answer:

the answer is B

Hope this helps!

Have a nice day :)

Explanation:

wel3 years ago
3 0
You’re answer should be B
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What kind of physics is used to describe the interaction of matter and energy from the beginning of the cosmic singularity to th
lisov135 [29]

Cosmology physics is used to describe the interaction of matter and energy from the beginning of the cosmic singularity to the Planck time.

Astronomy's field of cosmology examines the beginnings and development of the universe, from the Big Bang through the present and into the future. The current cosmology model for the development of the universe is the Big Bang theory, which relies on the validity of general relativity. There is a singularity there as well.

According to the Big Bang theory, the cosmos was once compressed into an infinitely small point 13.77 billion years ago. Prior to 10^{-43}seconds after the Big Bang, during the Planck Era, gravity, nuclear strong, nuclear weak, and electromagnetic forces are thought to have been merged into a single "super" force.

Learn more about big bang theory here;

brainly.com/question/18297161

#SPJ4

3 0
2 years ago
The student quickly discovers that placing the marshmallow over the flame is more effective than heating the marshmallow on the
ANEK [815]

Answer:

The answer is convection.

Explanation:

There are three types of heat transfer: conduction, convection and radiation.

  • Conduction occurs when two objects touch each other and transfer heat.
  • Convection occurs when an object heats its surrounding fluid (like air, or water) and, since the hot fluids are less dense than the cold ones, they go up. So convection is a type of heat transfer that usually goes from down to up.
  • Radiation occurs when objects emanate heat in the form of electromagnetic waves that propagates in all directions.

So in this case, when the marshmallow is above the fire, it is exposed to convection, which does not occur when it is on the side of the fire.

4 0
4 years ago
A photographer uses his camera, whose lens has a 50 mm focal length, to focus on an object 2.5 m away. He then wants to take a p
Temka [501]

Answer:

0.004 m away from the film

Explanation:

u = Object distance

v = Image distance

f = Focal length = 50 mm

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{0.05}-\frac{1}{2.5}\\\Rightarrow \frac{1}{v}=\frac{98}{5} \\\Rightarrow v=\frac{5}{98}=0.051\ m

The image distance is 0.051 m

When u = 50 cm

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{0.05}-\frac{1}{0.5}\\\Rightarrow \frac{1}{v}=18\\\Rightarrow v=\frac{1}{18}=0.055\ m

The image distance is 0.055 m

The lens has moved 0.055-0.051 = 0.004 m away from the film

3 0
3 years ago
Which property of sound waves decreases as the square of the distance from the source increases?
Vitek1552 [10]

Answer:

Intensity

Explanation:

The intensity of a sound wave is equal to the ratio between to the power emitted by the source divided by the area of the spherical surface through which the wave propagates:

I=\frac{P}{4\pi r^2}

where

P is the power

4\pi r^2 is the area of the spherical surface

r is the distance from the source

As we see from the formula, the intensity is inversely proportional to the square of the distance from the source:

I\propto \frac{1}{r^2}

so, intensity is the correct answer.

3 0
3 years ago
How much energy is transferred by five 60 watt bulb in 20 minutes
Annette [7]

(5 bulbs)·(60 watts/bulb)·(20 minutes)·(1 joule per sec/watt)·(60 sec/minute)

=  (5·60·20·1·60)  (bulb·watt·minute·joule per sec·sec) / (bulb·watt·minute)

=        360,000 joules
_____________________________________________

Another way:

Five 60-watt bulbs  =  300 watts  =  0.3 kilowatt

20 minutes  =  1/3 hour

              (0.3 kilowatt) · (1/3 hour)  =  0.1 kilowatt-hour
8 0
3 years ago
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