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Anika [276]
3 years ago
14

When the sound of source is moving away from the observer the observer will hear a

Physics
2 answers:
hammer [34]3 years ago
6 0

a sound of lower fequency

NNADVOKAT [17]3 years ago
6 0
Sound of lower frequency waves
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The friends start by discussing what they know with respect to electric and magnetic fields. Alexa mentions several differences
Sveta_85 [38]

Answer:

A. "The electric force vector is along the direction of the electric field, whereas the magnetic force vector is perpendicular to the magnetic field."

D. "The kinetic energy of a charged particle moving in an electric field is not altered, whereas the kinetic energy of a charged particle moving in a magnetic field is either increased or decreased, depending on the direction of motion."

Explanation:

Electric fields originate from voltage differences, the higher the voltage, the stronger the resulting field. Magnetic fields originate from electric currents, a stronger current results in a stronger field. An electric field exists even if there is no current. When there is current, the magnitude of the magnetic field will change with power consumption, but the strength of the electric field will remain the same.

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3 years ago
If an item as a density of.63 g/mL, when placed in water the item will
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Float. This is because water has a density of 1 g/ml, so anything less than this will float.

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4 years ago
Please help!!
Veronika [31]
The sound wave is 1.0 meters

8 0
3 years ago
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What is the difference between methane and fluorinated gases
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Methane is emitted during the production and transport of coal,natural gas,and oil,while fluorinated gases are emitted from a variety industrial processes.
6 0
4 years ago
The armature of a motor is accelerated uniformly from rest to a rotational velocity of 1800 rev/min in 10 seconds. the rotationa
Liono4ka [1.6K]
The initial angular velocity of the motor is zero, while the final angular velocity is 1800 rev/min. Let's convert this into rad/s, keeping in mind that
1 rev = 2 \pi rad
1 min = 60 s
we have
\omega_f = 1800  \frac{rev}{min}  \cdot  \frac{2 \pi rad/rev}{60 s/min}=188.4 rad/s

And so now we can calculate the angular acceleration of the motor:
\alpha =  \frac{\omega_f - \omega_i }{t} = \frac{188.4 rad/s -0}{10 s}=18.8 rad/s^2
7 0
4 years ago
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