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4 years ago

If ax+x^2=y^2-ay what is a in terms of x and y?

Mathematics

1 answer:

Marizza181 [45]4 years ago

3 0

Answer:

a = y - x.

Step-by-step explanation:

ax + x^2 = y^2 - ay

ax + ay = y^2 - x^2

a (x + y) = y^2 - x^2

a = (y^2 - x^2) / (x + y)

a = (y + x)(y - x) / (x + y)

a = y - x Answer.

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The car treves 15 milies in 3 hours.

solong [7]

9514 1404 393

Answer:

5 mph
50 miles

Step-by-step explanation:

To find miles per hour, divide miles by hours:

(15 mi)/(3 h) = 15/3 mi/h = 5 mi/h

To find distance, multiply speed by time.

(5 mi/h) × (10 h) = 50 mi

3 0

2 years ago

There are 40 girls and 60 boys in the math club the coach wants to divide the entire club into teams where each team has the sam

lapo4ka [179]

40 and 60
40 = 20 x 2
60 = 20 x 3

GCF = 20

the greatest number of teams coach can make is 20
each team can have 2 girls and 3 boys

6 0

3 years ago

What is the equation of a line that passes through the point (9, −3) and is parallel to the line whose equation is 2x−3y=6 ?

vlabodo [156]

2x - 3y = 6
-3y = -2x + 6
y = 2/3x - 2....the slope here is 2/3. A parallel line will have the same slope

y = mx + b
slope(m) = 2/3
(9,-3)...x = 9 and y = -3
now we sub and find b, the y int
-3 = 2/3(9) + b
-3 = 6 + b
-3 - 6 = b
-9 = b

so ur parallel equation is : y = 2/3x - 9 <== or 2x -3y = 27

6 0

3 years ago

Read 2 more answers

Line 1 passes through the points A(-15,-8) and B(-3,0). Line 2 has

Katyanochek1 [597]

Answer:

The equation of line 3 is;

y = $\frac{2}{3} x$ + 6

Step-by-step explanation:

Line 1 passes through the points A(-15,-8) andn B(-3,0)

Line 2 has equation shown below;

5x - 3y + 18 = 0

Line 3 is parallel to line 1 and has the same y-intercept as line 2.

We are to determine the equation of line 3.

Equation of line 1:

Slope = change in y-axis ÷ change in x-axis

The slope of line 1 = $\frac{0 - -8}{-3 - -15} = \frac{8}{12} = \frac{2}{3}$

Picking another point (x,y) on the line;

Slope = $\frac{y - 0}{x - -3} = \frac{2}{3}$

y = $\frac{2}{3} x$ + 2 (this is the equation of line 1)

Equation of line 2:

We put the equation given, of line 2, in the cartesian plane format;

3y = 5x + 18

y = $\frac{5}{3} x$ + 6

Finally, the equation of line 2 is;

y = 1 $\frac{2}{3} x$ + 6

Equation of line 3:

Given: Line 3 is parallel to line 1

The slopes of two parallel lines are the same so line 3 has a slope of $\frac{2}{3}$

Given: Line 3 has the same y-intercept as line 2

The y-intecept of line 2 is 6 (y-intercept is the value of y when x = 0)

So the equation of line 3 is;

y = $\frac{2}{3} x$ + 6

3 0

3 years ago

Se golpea (chuta) un balón sobre el piso y sale dando botes parabólicos cada vez menores. Si se lanzo inicialmente con una veloc

Ipatiy [6.2K]

Answer:

a)d = 180,91 m

b)t = 11,76 seg

Step-by-step explanation:

Para el lanzamiento de proyectil, la ecuación que nos da la velocidad en V(y) es:

V(y) = Voy - g*t

en donde Voy = Vo * senα ( donde Vo es la velocidad inicial, α el angulo del disparo.

Si en esta ecuación hacemos V(y) = 0 estamos en el punto donde el componente en el eje y de la velocidad del proyectil es cero, ese punto es el punto medio del recorrido.

0 = Vo*sen 60⁰ - g*t

g*t = Vo* √3/2

t = { 32 [m/s] * √3 }2*9,8 [m/s²]

t = 16*√3 / 9,8

t = 2,8278 seg

El tiempo total del primer recorrido es entonces por simetría

t₁ = 2 * 2,8278 t₁ = 5,6556 seg

La distancia del primer impacto al suelo es:

x = Vox * t₁ ( Vox es constante Vx = Vo*cos 60⁰ )

x = 32 * (1/2) * 5,6556

x₁ = 90,49 m

Aplicando los mismos criterios ahora para el segundo bote

Ahora Vo = 32 - 32*(1/4)

V = 24 m/s

g*t = 24 * sen 50⁰

t = 24* 0,7660/ 9,8

t = 1,8759

2*t = 2*1,8759

t₂ = 3,7518 seg

x₂ = Vox * t₂

x₂ = 24* 0,6428*3,7518

x₂ = 57,88 m

Y para el tercer bote Vo = 24 - 24(1/4) Vo = 18 m/s α = 40⁰

t = 18 *0,6428/9,8

t = 1,18

2t = t₃ = 2*1,18

t₃ = 2,36 seg

x₃ = Vox * 2,36 Vox = Vo*cos 40 Vox = 18*0,7660

Vox = 13,79

x₃ = 13,79*2,36

x₃ = 32,54 m

La distancia total será

d = x₁ + x₂ + x₃

d = 90,49 + 57,88 + 32,54

d = 180,91 m

y el tiempo total será la suma de los tiempos

t = t₁ + t₂ + t₃

t = 5,65 + 3,75 + 2,36

t = 11,76 seg

8 0

3 years ago