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3 years ago

If ax+x^2=y^2-ay what is a in terms of x and y?

Mathematics

1 answer:

Marizza181 [45]3 years ago

3 0

Answer:

a = y - x.

Step-by-step explanation:

ax + x^2 = y^2 - ay

ax + ay = y^2 - x^2

a (x + y) = y^2 - x^2

a = (y^2 - x^2) / (x + y)

a = (y + x)(y - x) / (x + y)

a = y - x Answer.

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The manager of hockey team says that the probability that team win the next match is 0.5 and the probability it will lose is 0.2

dybincka [34]

Answer:

Step-by-step explanation:

The team draws with a probability of 1 = (0.5 + 0.2) = 0.3

If the team does not win then it loses or draws.

Loosing = 0.2

Draw := 0.3

P(not win) = 0.2 + 0.3 = 0.5

======================

Not lose means wins or draws.

P(not lose) = 0.5 + 0.3 = 0.8

======================

Not Draw means wins or loses

P(not draw) = 0.5 + 0.2 = 0.7

Of course all of these could be done more directly.

P(not win)= (1 - win) = 1- 0.5 = 0.5

P(not lose) = ( 1 - lose) = 1 - 0.2 = 0.8

P(not draw) = (1 - 0.3) = 0.7

3 0

2 years ago

Express each ratio as a fraction in simplest form: 0.3 km to 500 m

deff fn [24]

0.3km=300m
300m:500m
(/100)
3:5
3+5=8
0.3km= 3/8
500m= 5/8

5 0

3 years ago

Read 2 more answers

60-5t is no more than 35 -5t is no more than -25t is at least 5 solve with correct answer

fiasKO [112]

The answer is 60-5t<35-5t<_25t>5

4 0

3 years ago

Which equation is equivalent to x2+10x+2=0 ?

Svet_ta [14]

x =(10-√92)/2=5-√ 23 = 0.204 or x =(10+√92)/2=5+√ 23 = 9.796

4 0

3 years ago

A sneaker company can make 50 pairs of sneakers for every 6 yards of material. Make a table to show the relation between materia

Law Incorporation [45]

A sneaker company can make 50 pairs of sneakers for every 6 yards of material.

Then in each case you can consider proportion.

1. 50 pairs -- 6 yards,

80 pairs -- x yards.

Mathematically,

$\dfrac{50}{80}=\dfrac{6}{x},\\ \\x=\dfrac{80\cdot 6}{50}=9.6\ yards.$

2. 50 pairs -- 6 yards,

100 pairs -- x yards.

Mathematically,

$\dfrac{50}{100}=\dfrac{6}{x},\\ \\x=\dfrac{100\cdot 6}{50}=12\ yards.$

3. 50 pairs -- 6 yards,

120 pairs -- x yards.

Mathematically,

$\dfrac{50}{120}=\dfrac{6}{x},\\ \\x=\dfrac{120\cdot 6}{50}=14.4\ yards.$

4. 50 pairs -- 6 yards,

140 pairs -- x yards.

Mathematically,

$\dfrac{50}{140}=\dfrac{6}{x},\\ \\x=\dfrac{140\cdot 6}{50}=16.8\ yards.$

Thus, the table is

$\begin{array}{cc}\text{Pairs}&\text{Yards}\\50&6\\80&9.6\\100&12\\120&14.4\\140&16.8\end{array}$

The domain of the relation is the set $\{50,80,100,120,140\}$ and the range of the relation is $\{6,9.6,12,14.4,16.8\}.$ See attached diagram for the graph of the relation.

4 0

2 years ago