Answer:
The first term is 14.
Step-by-step explanation:
The general formula for this kind of sequence (arithmetic) is a(n) = a(1) + (n-1)c, where c is the common difference. Here, we have a(6) = -1 = a(1) + (6-1)(-3), or -1 +15 = a(1). The first term is 14.
Answer:
x = 8
y = -7
Step-by-step explanation:
3y - 5x = -61
-----------------------+
-9x = -72
x = 8
3y -5(8) = -61
3y - 40 = -61
3y = -21
y = -7
Answer: y = 5x − 11
Step-by-step explanation:
The equation of a straight line can be represented in the slope-intercept form, y = mx + c
Where c = intercept
Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis represent
change in the value of y = y2 - y1
Change in value of x = x2 -x1
y2 = final value of y
y 1 = initial value of y
x2 = final value of x
x1 = initial value of x
The line passes through (3,4) and (2, -1),
y2 = - 1
y1 = 4
x2 = 2
x1 = 3
Slope,m = (- 1 - 4)/(2 - 3) = - 5/- 1 = 5
To determine the y intercept, we would substitute x = 3, y = 4 and m= 5 into
y = mx + c. It becomes
4 = 5 × 3 + c
4 = 15 + c
c = 4 - 15 = - 11
The equation becomes
y = 5x - 11
Answer:
Z = 0.198877274
Step-by-step explanation:

Hence, the value of Z = 0.198877274