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3 years ago

I have to find the area of the shape

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

5 0

The answer is 18m^2. if u find the area of each section and add it up together at the end then u get 18

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What is the approximate value of x in the triangle below

seraphim [82]

The value of x is: $6tan(35)$ , which is:
$6tan(35)=4.201$
Final Answer: B.) 4.2 units

5 0

3 years ago

Answer would be needed ! thanks

Vanyuwa [196]

55/A is the answer

Hope this helps

3 0

3 years ago

Read 2 more answers

What is the solution of StartRoot x + 2 EndRoot minus 15 = negative 3?

Brilliant_brown [7]

Answer:

x = 142

Step-by-step explanation:

The problem;

$\sqrt{x+2} - 15 = -3$

Inverse operations;

$\sqrt{x+2} -15 = -3\\ +15 +15\\\\\\\\\sqrt{x+2} = 12\\\\$

Now undo the square, by squaring both sides;

$\sqrt{x+2} = 12\\.^{2} \\\\\\ \\x+2 = 144$

Inverse oeprations;

x + 2 = 144

-2 -2

x = 142

8 0

3 years ago

Read 2 more answers

A quantity with an initial value of 9100 grows continuously at a rate of 0.85% per hour. What is the value of the quantity after

ycow [4]

Answer:

$10,962,54$

Step-by-step explanation:

we know that

The equation of a exponential growth is equal to

$y=a(1+r)^x$

where

a is the initial value

r is the rate of growth

x is the time in hours

y is the value of the quantity

we have

$a=9,100\\r=0.85\%=0.85/100=0.0085$

substitute

$y=9,100(1+0.0085)^x$

$y=9,100(1..0085)^x$

For x=22 hours

substitute

$y=9,100(1..0085)^{22} =10,962,54$

4 0

3 years ago

Determine the sample size needed to construct a 90% confidence interval to estimate the population proportion when p = 0.65 and

WINSTONCH [101]

Answer:

n=170

Step-by-step explanation:

1) Notation and definitions

$n$ random sample taken (variable of interest)

$\hat p=0.65$ estimated proportion.

$p$ true population

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.90=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by: