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3 years ago

How do u solve 90-2[60÷10]-4

Mathematics

2 answers:

Nikitich [7]3 years ago

8 0

You follow bedmas (brackets, exponents,division,multiplication,addition,subtraction). First comes the brackets so you do (60 divided by 10) which is 6. You still have (6) which means you have to multiply it by 2. So you get 12. Now you got rid of the brackets so you can solve the rest. 90-12-4= 74.

iogann1982 [59]3 years ago

6 0

90-2[60÷10]-4
90-(2*(60/10)) -4
<span>90-(2*6)-4
90-12-4
90-16
74</span>

hoped it helped!!!

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3 years ago

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MA_775_DIABLO [31]

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Answer:

Step-by-step explanation:

Let n, d, q represent the numbers of nickels, dimes, and quarters, respectively. Then we have ...

n + d + q = 45

5n +10d +25q = 700

n -d = -5

Using n=d -5, we can substitute into the first two equations:

(d -5) +d + q = 45

2d +q = 50 . . . . add 5, collect terms [eq4]

5(d -5) +10d +25q = 700

15d +25q = 725 . . . . . . . . . . add 25, collect terms [eq5]

Multiplying [eq4] equation by 3 and subtracting that from 2/5 of [eq5], we have ...

(2/5)(15d +25q) -3(2d +q) = (2/5)(725) -3(50)

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7q = 140 . . . . . . simplify

q = 20 . . . . . . . . divide by 7

There are 20 quarters.

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3 years ago

Prove the identity (sin6x)/(1+cos6x)=tan3x.

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4 years ago

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lys-0071 [83]

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