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4 years ago

11

ALEKKKKSS HELPPPPPPP!!!!!!!

1 answer:

RSB [31]4 years ago

8 0

Answer:

-7x

Step-by-step explanation:

This is actually simpler than you might think. Just subtract.

4x-11x

-7x

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Find the area of the figure.

Brums [2.3K]

Answer:

The area of a square:

$A = 37.21$ $m^2$

Step-by-step explanation:

The formula to find the area of a square:

$A = a^2$

Use the given measure for the formula:

$A = 6.1^2$

-Then, solve:

$A = 6.1^2$

$A = 37.21$

So, the area of a square is $37.21$ $m^2$ .

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3 years ago

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3 years ago

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professor190 [17]

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3 years ago

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What do you need to add to 3 5/7 to make 6

Aneli [31]

6 is equal to 42/7, and 3 and 5/7 is 26/7 so 42-26 = 16/7 which is also 2 and 2/7 ths

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3 years ago

4-(-3) as an addition problem and find the difference.

Naddika [18.5K]

$\huge\text{Hey there!}$

$\huge\boxed{\text{Guide \#1}\downarrow}$

$\bullet \huge\textsf{ Negative (-) \& negative (-) = positive (+)}$

$\bullet \huge\textsf{ Positive (+) \& negative (-) = negative (-)}$

$\bullet\huge\textsf{ Positive (+) \& positive (+) = positive (+)}$

$\bullet\huge\textsf{ Negative (-) \& positive (+) = negative (-)}$

$\huge\boxed{\frak{Guide\ \#2}\downarrow}$

$\bullet \huge\textsf{ Positives are on the RIGHT side of the}\\\huge\textsf{ number line}$

$\bullet\huge\textsf{ Negatives are on the LEFT side of the}\\\huge\textsf{ number line}$

$\huge\boxed{\bf Guide\ \#3\downarrow}}$

$\bullet\huge\textsf{ Positives are ABOVE 0}$

$\bullet\huge\textsf{ Negatives are BELOW 0}$

$\huge\boxed{Answering \ your \ question: }$

$\huge\boxed{\mathsf{4 - (-3)}}$

$\huge\boxed{\mathsf{= 4 + 3}}$

$\star \large\textsf{ You start at 4 and go up 3 spaces to the right because we are dealing with } \\\textsf{positive numbers on both right and left side }\star$ $\huge\boxed{\mathsf{= 4 + 3}}$

$\huge\boxed{\mathsf{= 7}}$

$\huge\boxed{\frak{\bold{Therefore, \ your \ \underline{\underline{answer \ is: \boxed{\frak 7}}}}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

<h2>~ $\huge\boxed{\rm{Amphitrite1040:)}}$ </h2>

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3 years ago

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