So the first one is (7x)^(1/2) or square root of 7x minus - 5 square root all squared so
([7x^(1/2)]-[5^(1/2)]) times ([7x^(1/2)]-[5^(1/2)])
or 7x-(35x^(1/2))-5+(35x^(1/2)) or 7x-5
number 2
since 11 is 1/2 of 22 it can be written as
the square root of 3 or 3^(1/2)
Answer:
B = (-11, -17)
C = (11, -17)
Step-by-step explanation:
Reflection over the x-axis is accomplished by changing the sign of the y-coordinate:
(x, y) ⇒ (x, -y) . . . . . reflection over x-axis
Reflection over the y-axis is accomplished by changing the sign of the x-coordinate:
(x, y) ⇒ (-x, y) . . . . . reflection over the y-axis
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B = (-11, -17)
C = (11, -17)
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<em>Check</em>
Reflection over both axes negates both coordinates. It is equivalent to reflection over the origin, or rotation 180°.
A(-11, 17) ⇒ C(11, -17) . . . . . both coordinates change sign
Your gonna wanna multiple (5/8)(5/8) which is 25/64 or about 39 percent. (I might not be entirely right, sorry. )
First, let's review the formula for the "sum of two cubes:"
a^3 + b^3 = (a + b)(a^2 - ab + b^2).
Unfortunately, 9 is not a perfect cube. The cube root of 9 is 9^(1/3), and the square of the cube root of 9 is therefore 9^(2/3).
Thus,
9x^3 + 64 = (9^(1/3)*x + 4) * (9^(2/3)x^2 - 4*9^(1/3) + 16)
X is 60, therefore, a = 120 and d = 60
