Question

An experiment using 35 guinea pigs is set up to study the weight of the pigs after injecting them with a drug. If the population mean is 23.5 grams with a standard deviation of 3.4 grams, what is the margin of error of the sample mean?

Answer 1

Answer:

1.1264

Step-by-step explanation:

Given : An experiment using 35 guinea pigs is set up to study the weight of the pigs after injecting them with a drug.

To Find: If the population mean is 23.5 grams with a standard deviation of 3.4 grams, what is the margin of error of the sample mean?

Solution:

n = 35

$\sigma = 3.4$

Confidence interval = 95%. So, z =1.96

Margin of error = $z \times \frac{\sigma}{\sqrt{n}}$

Margin of error = $1.96\times \frac{3.4}{\sqrt{35}}$

Margin of error = $1.1264$

Hence the margin of error of the sample mean is 1.1264.

Answer 2

Answer:

Margin of Error =  $\pm 0.1904$                  

Step-by-step explanation:

We are given the following information in the question:

Population mean, μ = 23.5 grams

Population standard deviation, σ = 3.4 grams

Sample size, n = 35

Alpha, α = 0.05

Formula:

$\text{Margin of Error} = z\displaystyle\frac{\sigma}{\sqrt{n}}$

where z is the z-critical at 0.05 level of significance.

Putting the values, we get:

z-critical at 0.05 level of significance = $\pm 1.96$

Margin of Error =

$\pm 1.96\displaystyle\frac{3.4}{\sqrt{35}} = \pm 1.1264$