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zvonat [6]
3 years ago
9

Maria who is 6 feet tall stand 20 feet away from the base of a tree she looks up at the top of the tree at 43° angle of elevatio

n what is the approximate height of the tree rounded to the nearest 10th but
Mathematics
1 answer:
grandymaker [24]3 years ago
4 0

Answer:

24.7 feet

Step-by-step explanation:

Maria who is 6 feet tall stands 20 feet away from the base of a tree she looks up at the top of the tree at a 43° angle of elevation.

what is the approximate height of the tree rounded to the nearest 10th?

We solve the above question using the Trigonometric function of Tangent

tan θ = Opposite/Adjacent

θ = Angle of elevation

Adjacent = Distance from the base of the tree = 20 feet

Opposite => Height of the tree = x

θ = 43°

tan 43 = x/ 20 feet

x = tan 43 × 20 feet

x = 18.650301723 feet

Approximately = 18.7 feet

We are told in the question that Maria is 6 feet tall

Therefore, the height of the tree = Maria's height + Height

= 6 feet + 18.7 feet

= 24.7 feet

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Sonbull [250]

Answer:

8.17 * 10^8

Step-by-step explanation:

Saturn is 9.1 * 10^8 miles from the sun, and earth is 9.3 * 10^7 miles from the sun. From this, we can see that Saturn is much farther from the sun than the earth.

To find the distance of one planet closer to the sun than the other planet, we can subtract 9.3 * 10^7 from 9.1 * 10^8.

Original expression: 9.1 * 10^8 - 9.3 * 10^7

Convert both sides to 10^7: 91 * 10^7 - 9.3 * 10^7

Subtract: 81.7 * 10^7

Simplify: 8.17 * 10^8

Let me know if this helps!

6 0
3 years ago
Find m∠U.<br> Write your answer as an integer or as a decimal rounded to the nearest tenth.
olga2289 [7]

Answer:

Answer:

50.2

Step-by-step explanation:

ut =  \sqrt{ {6}^{2}  +  {5}^{2} }   \\  \sqrt{36 + 25}  \\  \sqrt{61 }  \\ using \: cosine \: rule \\ cos \: u =  \frac{ {5}^{2} + 61 - 36 }{2 \times 5 \times  \sqrt{61} }  \\  \\  =  \frac{25 + 61 - 36}{78}  \\  \\  = \frac{50}{78 }  \\  \cos \: u = 0.64 \\ m∠U. = 50.2

7 0
2 years ago
How do you solve this problem?
enot [183]
Easy, it says "for ANY positive integer" so just test any positive integer

remember that n! means times all integers from 1 to that number n

lets try 1

(1+1)!/(1!)-1=
(2!)/(1!)-1=
2/1-1=
2-1=
1

if you don't believe me, try 2
(2+1)!/(2!)-2=
(3!)/(2!)-2=
(6)/(2)-2=
3-2=
1

te answer is 1, B


and number 9
easy, remember the exponential law
(x^m)(x^n)=x^(m+n)
jsut add the exponents
first gropu like bases
(r^2r^2/3)(t^1/2t^-3/2)
add bases
(r^2 and 2/3)(t^-1)=
(r^2∛(r^2))(1/t)=
\frac{r^{2} \sqrt[3]{r^{2}} }{t}
5 0
3 years ago
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In between the first year
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Answer:

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4 0
3 years ago
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