Answer:
7.9Hz
Explanation:
Step one:
given data
We are told that the fourth harmonic is at 31.5 Hz
We know that harmonics are a multiple of the fundamental frequency, such that if the fundamental frequency is 25Hz, then the second harmonic is
2nd= 2*25= 50Hz
3rd= 3*25= 75Hz........and so on
Step two:
In this problem, we are told that the 4th harmonic is 31.5Hz, that is
4th= 4*f= 31.5
Divide both sides by 4 to get f
f= 31.5/4
f= 7.9 Hz
Hence the first/fundamental frequency is 7.9Hz
Answer:
Es útil porque al saberlo evitas sobrexponerte a problemas como <em><u>enfermedades, desgarros o daños a largo plazo de tu cuerpo.</u></em>
Explanation:
When a person decides to start exercising or some type of physical activity, it is necessary for him to know how much his body can resist that activity during a defined period of time.
If in some way or another your body does not resist physical activity, you can hurt yourself, tear a ligament or muscle or get sick.
One of the most common diseases that almost nobody notices is the increase in circulatory and heart problems.
It is best to know your physical condition, how much weight you can carry with weights, or how long you can last doing physical activities.
Answer:
false
Explanation:
the temperature of an object is a measure of the average KINETIC ENERGY of the molecules in the object (not potential energy)
F = GMm/r^2
So F is proportional to 1/r^2
F2 = 2700 x ( 1 / 3^2 ) = 300N
Answer:
This could represent something like sliding a small rock across an icy lake.
Explanation:
A 20N force of gravity (weight), and 20N normal force exerted back onto the object imply it is on the ground and has no vertical motion. There is a net force of 0N
An 80N force to the left and a 5N force to the right create a net force of 75N to the left. This means that there is a force acting on the object that makes it accelerate to the left. 80N represents a push or pull force and 5N represents a relatively small frictional force due to the object being slid on a surface such as steel or in this case ice.