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2 years ago

A local school has was evaluated the the Education Department and received the

Mathematics

1 answer:

Angelina_Jolie [31]2 years ago

5 0

Answer: 79

Step-by-step explanation:

Given the following :

Graduation Rates:

Grade:82

Weight: 50%

Passing Rates:

Grade: 75

Weight: 30%

Enrollment Numbers:

Grade: 60

Weight: 10%

Career readiness:

Grade: 95

Weight: 10%

Overall score : Σ(grade × weight)

(82 × 50%) + (75 × 30%) + (60 × 10%) + (95 × 10%)

= (41 + 22.5 + 6 + 9.5)

= 79

Hence, overall score is 79

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Show a way to count from 668 to 900 using ones tens and hundreds

cricket20 [7]

Hey there!

You can count from 668 to 900 using the following:

668 → 768 → 868 (two 100s)

868 → 878 → 888 → 898 (three 10s)

898 → 899 → 900 (two 1s)

Hope this helped you out! :-)

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2 years ago

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bagirrra123 [75]

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3 years ago

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Simplify using i 3+2i/6+5i

alukav5142 [94]

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2 years ago

Find the length of segment GH.<br> 21<br> 12<br> F

jek_recluse [69]

Answer:

GH = 9

Step-by-step explanation:

FH=FG+GH

21= 12+GH

GH = 21-12 =9

I hope I helped you^_^

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2 years ago

Find the Area of the figure below, composed of a rectangle and a semicircle. Round to the nearest tenth place.

kap26 [50]

Answer: 68.1

Step-by-step explanation:

The area of a semi-circle is 1/2 the area of a full circle. The area of a full circle is pi*r^2. Therefore, the area of a semi-circle is:

$Area=\pi r^2/2$

$Area=\pi (3)^2/2=9\pi /2$

The area of a rectangle is the length multiplied by the width:

$Area=l*w$

$Area=6*9=54$

The net area is the sum of the rectangle and the semi-circle:

$Area=(9\pi /2)+(54)=68.1$

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2 years ago