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IgorC [24]
3 years ago
15

A local school has was evaluated the the Education Department and received the

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
5 0

Answer: 79

Step-by-step explanation:

Given the following :

Graduation Rates:

Grade:82

Weight: 50%

Passing Rates:

Grade: 75

Weight: 30%

Enrollment Numbers:

Grade: 60

Weight: 10%

Career readiness:

Grade: 95

Weight: 10%

Overall score : Σ(grade × weight)

(82 × 50%) + (75 × 30%) + (60 × 10%) + (95 × 10%)

= (41 + 22.5 + 6 + 9.5)

= 79

Hence, overall score is 79

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Please help me. ASAP.Please I need answer step-by-step.
nikitadnepr [17]

so this is how i was taught the inverse function.  f(x) is basicly the same thing as saying y

so y=x over x+3  

you switch the top x with y so it turns in to x=y over x+3

the problem should tell you what x equals so substitute x with the number it equals and then solve

here is an example f(x)=x over x+3 and x=14

x=y over x+3

14=y over 14+3

the inverse inverse function would probably be just solve the equation so just substitute the number they give you for x in for x

4 0
4 years ago
What is the simplified form of the expression 1/2 (2x + 6).
kakasveta [241]
1/2(2x+6)
Substitute the one half to both of the numbers inside the parentheses.
1/2*2 is one which would just be x
1/2*6 is three
X+3
8 0
3 years ago
Read 2 more answers
Ralph is an electrictian.he charges an initial fee of $32 plus $33 per hour. If Ralph earned $189 on a Job,how long did The Job
aleksley [76]

Answer:

5 hours

Step-by-step explanation:

189-32=157

157/33 is about 4.76

4.76 rounded is 5 so the job took 5 hours

6 0
3 years ago
What is the value of the expression (2)^6?<br>pls help ​
Ronch [10]

Answer:

64

Step-by-step explanation:

2^6, or 2⁶, is two to the power of six.

Basically you multiply the bottom number (in this case 2) by itself as many times as the the number in the top right (in this case six)

2^6=2*2*2*2*2*2=64

8 0
3 years ago
Read 2 more answers
The question is:
saul85 [17]
f(x) = \sqrt{x+1} \\ y = \sqrt{x+1} \ or \ y^2 = x+1 \ or \ x = y^2 - 1 \\ Therefore, \ f^{-1}(x)=x^2 - 1

(fof^{-1})(a) = f(f^{-1}(a))=f(a^2-1) \\ =\sqrt{a^2-1+1}=\sqrt{a^2}=a \\  \\ (f^{-1}of)(a)=f^{-1}(f(a))=f^{-1}(\sqrt{a+1})= \\ (\sqrt{a+1})^2-1 = a+1-1 = a

Therefore, (fof^{-1})(a) = (f^{-1}of)(a) = a

8 0
3 years ago
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