Answer:
1.78 J
Explanation:
Find the spring coefficient using Hooke's law:
F = k Δx
23 N = k (0.20 m − 0.14 m)
k = 383.33 N/m
The work is the change in energy:
W = PE₂ − PE₁
W = ½ kx₂² − ½ kx₁²
W = ½ k (x₂² − x₁²)
W = ½ (383.33 N/m) ((0.17 m)² − (0.14 m)²)
W = 1.78 J
Answer:
a) v₀ = 9.2 m/s
b) y₀ = 7.9 m
Explanation:
The position of the balls is given by the equation:

where:
acceleration g = 9.8 m/s²
time t
initial velocity v₀
initial height y₀
a) lets divide (a) in two parts:
1.part: How long will it take the second ball to fall down?

2. part: At time t from part1 + 1.15s, the first ball should land on the ground.

This leaves only one unknown: v₀

b)again, lets divide in two parts
1.part: Where will ball1 be relative to ball2 in 1.15s:

and how fast will it go:

2.part: Now we can plug in to the equation for the position of the two balls. Let's start with the second ball first:

Now let's use this result in the equation for the first ball:

Acceleration= change in velocity/time=27.8-0/4.8=5.792 ms⁻²
Force= Mass*acceleration=66*5.792=382.25 N
Waves are either transversal stereotypical pictures of waves or longitudinal it goes in rings waves are just different forms of vibration of any kind of energy