Answer:
Explanation:
400 W = 400 J/s
300000 J / 400 J/s = 750 s or 12.5 minutes
I’m not sure if this will help but I found: https://prezi.com/l0fa6du3b9kp/going-off-the-grid-assignment/?fallback=1 and
Answer:
![\boxed {\boxed {\sf v_i= 4 \ m/s}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%20v_i%3D%204%20%5C%20m%2Fs%7D%7D)
Explanation:
We are asked to find the cyclist's initial velocity. We are given the acceleration, final velocity, and time, so we will use the following kinematic equation.
![v_f= v_i + at](https://tex.z-dn.net/?f=v_f%3D%20v_i%20%2B%20at)
The cyclist is acceleration at 1.2 meters per second squared. After 10 seconds, the velocity is 16 meters per second.
= 16 m/s - a= 1.2 m/s²
- t= 10 s
Substitute the values into the formula.
![16 \ m/s = v_i + (1.2 \ m/s^2)(10 \ s)](https://tex.z-dn.net/?f=16%20%5C%20m%2Fs%20%3D%20v_i%20%2B%20%281.2%20%5C%20m%2Fs%5E2%29%2810%20%5C%20s%29)
Multiply.
![16 \ m/s = v_i + (1.2 \ m/s^2 * 10 \ s)](https://tex.z-dn.net/?f=16%20%5C%20m%2Fs%20%3D%20v_i%20%2B%20%281.2%20%5C%20m%2Fs%5E2%20%2A%2010%20%5C%20s%29)
![16 \ m/s = v_i + 12 \ m/s](https://tex.z-dn.net/?f=16%20%5C%20m%2Fs%20%3D%20v_i%20%2B%2012%20%5C%20m%2Fs)
We are solving for the initial velocity, so we must isolate the variable
. Subtract 12 meters per second from both sides of the equation.
![16 \ m/s - 12 \ m/s = v_i + 12 \ m/s -12 \ m/s](https://tex.z-dn.net/?f=16%20%5C%20m%2Fs%20-%2012%20%5C%20m%2Fs%20%3D%20v_i%20%2B%2012%20%5C%20m%2Fs%20-12%20%5C%20m%2Fs)
![4 \ m/s = v_i](https://tex.z-dn.net/?f=4%20%5C%20m%2Fs%20%3D%20v_i)
The cyclist's initial velocity is <u>4 meters per second.</u>
Answer: The velocity with which the sand throw is 24.2 m/s.
Explanation:
Explanation:
acceleration due to gravity, a = 3.9 m/s2
height, h = 75 m
final velocity, v = 0
Let the initial velocity at the time of throw is u.
Use third equation of motion
The velocity with which the sand throw is 24.2 m/s.
For any object thrown upwards where only the force of gravity is acting upon it, uses the following formula for the maximum height attained.
H= v²/2g, where g = 9.81 m/s²
There are two information of velocities are given. However, we use the 20 m/s information because this is the launch velocity. Hence, the solution is as follows:
H = (20 m/s)²/2(9.81 m/s²)
<em>H = 20.4 m</em>