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2 years ago

The volume of a sphere whose diameter is 18 cm is

Mathematics

1 answer:

prohojiy [21]2 years ago

5 0

Answer:

= 3052.08 cm^3

Step-by-step explanation:

Volume of a sphere is given by

V = 4/3 pi r^3

We know the diameter is 18

d = 2r

18 = 2r

Divide each side by 2

18/2 =2r/2

9 =r

V = 4/3 pi 9^3

V = 4/3 pi (729)

V = 972 pi

Approximating pi by 3.14

V =972 (3.14)

= 3052.08 cm^3

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Nicole has $9 to spend on cards. She finds friends with the same amount of money to split the cost of a set. One set costs $27.

azamat

Each friend gets three cards.

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2 years ago

Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar

oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 18 means that $N = 18$

9 are carrying nuclear weapons, which means that $k = 9$

9 are destroyed, which means that $n = 9$

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X \leq 1) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021$

$P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687$

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

4 0

2 years ago

The population of a city has increased by 27% since it was last measured. If the current population is 38,100, what was the prev

adoni [48]

Answer:

the previous population was 62,000.

Step-by-step explanation:

The current population of a city = 83,700

The population of a city has increased by 35% since it was last measured.

We have to calculate the previous population before increasing 35%.

Let the previous population be p

p +(35% × p) = 83,700

p + 0.35p = 83,700

1.35p = 83,700

p =

p = 62,000

Therefore, the previous population was 62,000.

3 0

2 years ago

Read 2 more answers

3 tenths +4 tenths +__________tenths

algol [13]

Well four plus seven would equal seven tenths.

6 0

2 years ago

Are 12:14 and 60:70 equivalent ratios?<br><br> yes<br> no

NNADVOKAT [17]

Answer:

Yes, they are equalent

Step-by-step explanation:

12:14 = 6:7

60:70 =6:7

both can be simplified to 6:7

5 0

2 years ago