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Kaylis [27]
3 years ago
8

Can you plz help me with the following questions

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
7 0

5+8e > 76\qquad\text{subtract 5 from both sides}\\\\8e > 71\qquad\text{divide both sides by 8}\\\\\boxed{e=\dfrac{71}{8}}


e\cdot7

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If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person se
notsponge [240]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 5

What is the probability that a person selected at random will have an IQ of 110 or higher?

This is 1 subtracted by the pvalue of Z when X = 110. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 100}{5}

Z = 2

Z = 2 has a pvalue of 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or higher

5 0
3 years ago
Simplify this expression. Enter your answers in the boxes.<br><br> 8.9 – 1.4x + (–6.5x) + 3.4
densk [106]

Answer:

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Step-by-step explanation:

8.9+3.4=12.3

-1.4x+(-6.5x)=-7.9x

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3 years ago
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What you do is you “take apart” the net so it has individual rectangles, then you multiply the 2 sides... you do that for each rectangle then add it all up
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3 years ago
What is the solution to the equation <br><img src="https://tex.z-dn.net/?f=2x%20-%207%20%3D%206x%20%2B%201" id="TexFormula1" tit
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Answer:

;lkjjjhhghhhhhhhiokjml,.

Step-by-step explanation:

7 0
3 years ago
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