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erma4kov [3.2K]
2 years ago
11

HELP PLEASE!! Write an equation in slope-intercept form of the line with slope −6/5 that contains the point (−5,3).

Mathematics
2 answers:
olga nikolaevna [1]2 years ago
6 0

Answer:


Step-by-step explanation:

we know,

Equation of line with slope m

and passing through (x1,y1)  is,

y-y1=m(x-x1)

here, slope= -6/5 and the point is  (-5,3)

So, the equation is,

y-3=-\frac{6}{5} (x-(-5))\\or, y-3=-\frac{6}{5} (x+5)\\

Multiplying by  5

5(y-3)=-6(x+5)\\or, 5y-15=-6x-30\\or, 5y=-6x-30+15\\or, 5y=-6x-15\\

Dividing by  5

y=-\frac{6}{5} x-3

xz_007 [3.2K]2 years ago
5 0

Answer: y = -6/5 x - 3

Solution :

The equation of line is  

y = mx + b  

y = y coordinate  

m = slope

x = x coordinate

b = y intercept

so to write the equation of line we need to find the y-intercept (b)

substitute the slope (-6/5) and coordinates given (-5,3) ,

y = mx + b

3 = (-6/5) (-5) + b

3 = 6 + b

3 - 6 = b

-3 = b

So the equation would be,

y = mx + b

y = -6/5 x - 3





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Answer:

See explanation below.

Step-by-step explanation:

Assuming this problem: "According to New Jersey Transit, the 8:00 A.M. weekday train from Princeton to New York City has a 90% chance of arriving on time on a randomly selected day. Suppose this claim is true. Choose 6 days at random. Let W = the number of days on which the train arrives late. "

For this case we can check if the binomial model can be used checking conditions:

1) We satisfy that we have independent trials and is assumed for this case

2) We have a fixed value for the trials n =6 and for the probability p = 0.9 on each trial

3) We have bernoulli experiments on each trial since we have success or failure for each case.

So then since all the conditions are satisfied we can assume that the binomial model can be used here.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let W the random variable of interest "the number of days on which the train arrives late", on this case we now that:

W \sim Binom(n=6, p=0.9)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

We can find all the possible probabilities for all the possible values of X like this:

P(X=0)=(6C0)(0.9)^0 (1-0.9)^{6-0}=1x10^{-6}

P(X=1)=(6C1)(0.9)^1 (1-0.9)^{6-1}=5.4x10^{-5}

P(X=2)=(6C2)(0.9)^2 (1-0.9)^{6-2}=0.001215

P(X=3)=(6C3)(0.9)^3 (1-0.9)^{6-3}=0.01458

P(X=4)=(6C4)(0.9)^4 (1-0.9)^{6-4}=0.0984

P(X=5)=(6C5)(0.9)^5 (1-0.9)^{6-5}=0.354

P(X=5)=(6C5)(0.9)^6 (1-0.9)^{6-6}=0.531

4 0
3 years ago
The box plots show the math scores of students in two different classes:
mezya [45]

Answer:

1st statement

Step-by-step explanation:

The line inside the box is the median.
Since in Class A the median line is on around 80 whilst Class B's median is 75.

So Median of

Class A > Class B

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9. What is the equation of a line perpendicular to 3x – 4y = 24 ?
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6 0
3 years ago
a man invests a total of 5000 in a bank account that yields 5% interest compound monthly. how much will it be worth after 6 year
kaheart [24]

Answer:

  6745.09

Step-by-step explanation:

If we assume the nominal annual interest rate is 5%, then the future value after 6 years is ...

  FV = P(1 +r/12)^(12·t)

for P = 5000, r = .05, t = 6.

Doing the arithmetic, we get ...

  FV = 5000(1 +.05/12)^(12·6) ≈ 6745.09

After 6 years, the bank account will be worth 6745.09.

_____

We made a comment about the interest rate, because the annual <em>yield</em> is about 5.116%. If the <em>annual yield</em> is actually 5%, then the account value is lower: $6700.48. (Monthly compounding is irrelevant in that case, because it is already figured into the yield.)

Usually, the wording would be that the account <em>earns</em> 5% interest compounded monthly.

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Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 l
slamgirl [31]

Answer:

She will leave an extra video game which weighs 0.25lb

Step-by-step explanation:

Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 lb), and a music player (0.4 lb). Using the inequality x ≤ 2.25, can she add all these items to the suitcase? If not, what could be left out to be closest to the maximum weight allowed?

Solution:

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hand-held video game = 0.6 lb

an extra video game = 0.25 lb music player = 0.4 lb

The total weight of the items

= 1.25lb + 0.25lb + 0.6lb + 0.4lb

= 2.5 lb.

Total weight - required weight

= 2.5lb - 2.25lb

= 0.25lb

2.5lb is 0.25lb greater than 2.25lb

Therefore, not all items can be added.

She has to leave out an item equivalent to 0.25lb

Item equivalent to 0.25lb is the extra video game

If Li leaves out the extra game, which weighs 0.25 lb, she’d have the maximum weight allowed.

5 0
2 years ago
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