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snow_lady [41]
2 years ago
14

A delinquent is able to accelerate a 200 g snowball from rest to a speed of 20 m/s over a distance of 1.2 m. What is the work (i

n J) done on the ball by this troubled youth? You may assume that the snowball travels perfectly horizontally (i.e., parallel to the ground) during its acceleration.
Business
1 answer:
Pavel [41]2 years ago
3 0

Answer:

40 J

Explanation:

Using equation of linear motion

v² = u² + 2as

where v is final velocity attain, u is initial velocity which is = 0 m/s since it is starting from rest, a is acceleration in m/s² and s is the distance covered

(20 m/s)² = 0 + 2 a × 1.2 m

400 / 2.4 = a

a = 166.67 m/s²

F = ma = 0.2 × 166.67 = 33.33 N

work done by the troubled youth = force × distance = 33.33 × 1.2 m = 40 J

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