Answer:
Step-by-step explanation:
1. cannot be determined. We don't have all the numbers so you can't find the mean (average).
2. True. The median is the line in the middle of the box. The median for movie 1 is greater than 600 and the median for movie 2 is less than 600.
3. True. Interquartile range is the biggest number of the box minus the smallest number of the box. Movie 1 is approximately 200 and movie 2 is approximately 70.
4. True. Q3 is the last line of the box.
Answer:
50 soldiers must be transferred elsewhere.
Step-by-step explanation:
We solve this question by proportions, using a rule of three.
As the number of soldiers decrease, the provisions last for more time. This means that the measures are inversely proportional, and we have an inverse rule of three, using line multiplication, instead of cross.
30 days of provisions - 200 soldiers
40 days of provisions - x soldiers
Simplifying by 40
The provisions will last for 40 days with 150 soldiers, which means that 200 - 150 = 50 soldiers must be transferred elsewhere.
Answer:
y= -2x-7
Step-by-step explanation:
point-slope: y-y1=m(x-x1)
y-3=-2(x-5)
y-3=-2x-10
y=-2x-7
56 miles, The car traveled m miles during the first hour and m squared miles during the second hour. The ratio m/m squared = 1/7 and cross multiplying yields m squared = 7m, so m=7. This means that the total distance traveled was 7+7squared = 56 miles
Answer:
Step-by-step explanation:
d/dn(2 n^2 + 12 n + 18) = 4 (n + 3)
Indefinite integral:
integral(18 + 12 n + 2 n^2) dn = (2 n^3)/3 + 6 n^2 + 18 n + constant
Global minimum:
min{2 n^2 + 12 n + 18} = 0 at n = -3
