3 years ago

Solve by factoring2n^2+12n+18

Mathematics

1 answer:

Gelneren [198K]3 years ago

8 0

Answer:

Step-by-step explanation:

d/dn(2 n^2 + 12 n + 18) = 4 (n + 3)

Indefinite integral:

integral(18 + 12 n + 2 n^2) dn = (2 n^3)/3 + 6 n^2 + 18 n + constant

Global minimum:

min{2 n^2 + 12 n + 18} = 0 at n = -3

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Step-by-step explanation:

Solution:

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