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3 years ago

22/110 to its lowest terms

2 answers:

3 0

Find the GCF, in this case 11, and divide both the numerator and denominator by it. Here, it turns out to be 2/11 because 22÷11 is 2 and 110÷11 is 11.

lys-0071 [83]3 years ago

3 0

22/110 =

divide 22 and 110 by 22

and your answer is:

1/5 as fraction or 0.2 as decimal

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HELP WILL GIVE BRAINLIST PLSSSSS I WILL GIVE YOU 79 POINTS IF YOU GET IT RIGHT JUST PLSS HELP ME

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Answer:

Step-by-step explanation:

the bottom one on the right

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3 years ago

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Simplify the rational expression by rationalizing the denominator √15/√6x

noname [10]

Answer:

√10/2x

Step-by-step explanation:

Multiply by √6 on the top and bottom to rationalize the denominator.

(√15×√6)/(√6x×√6) = √90/6x = (√9×√10)/6x = 3√10/6x = √10/2x

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3 years ago

While traveling to the office, dolly drives her car at a speed of 60 kmph and then suddenly the car stopped on half of her dista

lisabon 2012 [21]

The average speed of Dolly is 33.33kmph.

Average Speed:

The average speed is defined as the total distance travelled by the object in a particular interval of time. It can be calculated by dividing the total distance travelled by the total time taken.

So, Average Speed = total distance / total time

Here,

Let the total distance is 100 km.

Therefore, consider she will travel 60 km at speed of 60 kmph , 30 km at speed of 30 kmph and 10 km at speed of 10 kmph.

she will required times of 1 hour, 1hour and 1hour

So,

Average speed = 100 / (1 + 1 + 1)

=> 100 / 3 = 33.33

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6 0

2 years ago

There are

maria [59]

1 because 5÷3=1 and a remainder of 2 students.

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4 years ago

In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g

KIM [24]

Answer:

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

All girls from the first group:

20 students, so $N = 20$

10 girls, so $k = 10$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163$

All girls from the second group:

20 students, so $N = 20$

5 girls, so $k = 5$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006$

All girls from the third group:

20 students, so $N = 20$

8 girls, so $k = 8$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036$

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

$P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}$

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

7 0

3 years ago