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That number is already in standard form.
If you need to write it in scientific notation, then do this.
<span>731,934,000
Look at all the digits that are not zero, and place the decimal point in a way that you have a number from 1 to less than 10.
Take 731934, and place the decimal point after the 7 giving 7.31934.
The original decimal point was after the third zero, so now using the original number, count the number of decimal places you moved the decimal point. The decimal point moved 8 places to the left. That means you need an exponent of 8.
</span>
If you need to write it in scientific notation, then do this.
<span>731,934,000
Look at all the digits that are not zero, and place the decimal point in a way that you have a number from 1 to less than 10.
Take 731934, and place the decimal point after the 7 giving 7.31934.
The original decimal point was after the third zero, so now using the original number, count the number of decimal places you moved the decimal point. The decimal point moved 8 places to the left. That means you need an exponent of 8.
</span>
<em><u>Question:</u></em>
At the city museum, child admission is $5.80 and adult admission is $9.30. On Monday, four times as many adult tickets as child tickets were sold, for a total sales of $1548.00. How many child tickets were sold that day?
<em><u>Answer:</u></em>
36 child tickets were sold
<em><u>Solution:</u></em>
Given that,
Cost of 1 child admission = $ 5.80
Cost of 1 adult admission = $ 9.30
Let "c" be the number of child tickets sold
Let "a" be the number of adult tickets sold
On Monday, four times as many adult tickets as child tickets were sold
Number of adult tickets sold = four times the number of child tickets
Number of adult tickets sold = 4(number of child tickets sold)
a = 4c ----- eq 1
They were sold for a total sales of $ 1548.00
number of child tickets sold x Cost of 1 child admission + number of adult tickets sold x Cost of 1 adult admission = 1548.00
5.8c + 9.3a = 1548 ---- eqn 2
Let us solve eqn 1 and eqn 2 to find values of "c" and "a"
Substitute eqn 1 in eqn 2
5.8c + 9.3(4c) = 1548
5.8c + 37.2c = 1548
43c = 1548
c = 36
Thus 36 child tickets were sold that day