2a + 4 > 12<br><br> qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq

Ke in order to repay the mo 92 - (12 + 16) 4 Gracie need to make in order

valentinak56 [21]

Good question i just can't figure it out!

3 0

3 years ago

Question !<br>Qa/ 4.2 - 1.5² +0.3 x0.7

Wewaii [24]

Step-by-step explanation:

8x+8−3(x+4)−7(2−x)

8x+8−(3x+12)−7(2−x)

8x+8−(3x+12)−(14−7x)

8x+8−3x−12−14+7x

(8x−3x+7x)+(8−12−14)

12x-18

5 0

3 years ago

Rewrite the fraction 14 as a division expression with the same numbers.

GalinKa [24]

Answer:

7/50

Step-by-step explanation:

4 0

3 years ago

Multiple-choice questions each have four possible answers left parenthesis a , b , c , d right (a, b, c, d), one of which is co

arlik [135]

A) Since there are four multiple choice questions Which has one correct answer. The probability of choosing a correct answer is

$P(C) = \frac{1}{4}$

The probability of choosing wrong answer is

$P(W) = \frac{3}{4}$

Using the multiplication rule
$P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}$

b) If you guess answers to three of the questions, then the possibilities of getting one correct answer are:

Either the first two are wrong and the third one is correct. This will give the arrangement;

$WWC$

Or the first is wrong the second one is correct and the last one is wrong. This will give the arrangement,

$WCW$

Or the first one is correct and the last two are wrong. This will give the arrangement,

$CWW$
.

$P(WWC) = P(W) \times P(W) \times P(C) \\ \\ P(WWC) = \frac{3}{4} \times \frac{3}{4} \times \frac{1}{4} \\ \\ P(WWC) = \frac{9}{64}$

$P(WCW ) = P(W) \times P( C ) \times P(W) \\ \\ P(WCW) = \frac{3}{4} \times \frac{1}{4} \times \frac{3}{4} \\ \\ P(WCW) = \frac{9}{64}$

$P(CWW ) = P(W) \times P( C ) \times P(W) \\ \\ P(CWW) = \frac{1}{4} \times \frac{3}{4} \times \frac{3}{4} \\ \\ P(CWW) = \frac{9}{64}$

c) The probability of getting one correct answer is either the first one is correct or second is correct or third is correct.

$P(One \: Correct)= P(CWW) \: or P(WCW) \: or \: P(WWC) \\ \\ P(One \: Correct)= P(CWW) \: + P(WCW) \: + \: P(WWC) \\ \\ P(One \: Correct)= \frac{9}{64} + \frac{9}{64} + \frac{9}{64} \\ \\ P(One \: Correct) = \frac{27}{64}$

7 0

3 years ago

Read 2 more answers

MARKING BRAINIEST!

Svetlanka [38]

Answer:

(0, 4)

(1, 5)

(-1, 3)

Step-by-step explanation:

the function is already in slope-intercept form (y=mx+b). B is the y intercept and mx is the slope. The equation y=x+4 means that there is a y intercept of 4 and a slope of 1. So, y intercept is when x is equal to 0 which means one of your points will be (0,4). The next point will be 1 unit up and 1 unit to the right of the point (0, 4) and the third point will be 1 unit down and 1 unit to the left of (0, 4). This gives you the points (1, 5) and (-1, 3)

6 0

3 years ago

Read 2 more answers

2a + 4 > 12 qqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq