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Kitty [74]
2 years ago
7

Could someone explain things like radicals with variables that are raised to powers. plz,

Mathematics
1 answer:
Setler79 [48]2 years ago
5 0

When radicals (square roots) include variables, they are still simplified the same way. We just have to work with variables as well as numbers

1) Factor the radicand (the numbers/variables inside the square root). Factor the number into its prime factors and expand the variable(s).

2) Bring any factor listed twice in the radicand to the outside

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The sum of the square root of a number and 6
Anna007 [38]

Answer:

36

Step-by-step explanation:

4 0
3 years ago
What is the probability of getting exactly 5 “heads” in 10 coin flips ?
castortr0y [4]

There are \dbinom{10}5=\dfrac{10!}{5!(10-5)!}=252 ways of getting exactly 5 heads in 10 tosses. There are 2^{10}=1024 possible outcomes. So the probability of getting exactly 5 heads is

\dfrac{252}{1024}=\dfrac{63}{256}\approx24.61\%

6 0
3 years ago
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Solve the equation.<br> (10x + 5) + (6x − 1) = 180<br><br> A. 9<br> B. 11<br> C. 17<br> D. 23
cluponka [151]
(10x+5) + (6x-1)=180
10x+5+6x-1=180
16x+4=180
16x+4=180
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16x=178
x=11
3 0
3 years ago
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Please xplain and help with answers
Amiraneli [1.4K]

Step-by-step explanation:

for mixed number to a improper fraction you take the whole number and times that by the denominator and add the numeriator

for example

8 \frac{3}{8}

8 x 8 = 64

64 + 3 = 67

and after you get your last number (67) you put that over your original denominator which is 8 so it would be

\frac{67}{8}

for the improper to mixed you see how many times you denominator goes into your numerator

another example is

\frac{13}{7}

7 goes into 13 twice so your whole number is 2 and you have a remaining 1 so it would look like

2 \frac{1}{7}

8 0
3 years ago
Read 2 more answers
F=9/5c+32 solve for c
Paraphin [41]

Answer:

5/9 (F-32)=c

Step-by-step explanation:

F=9/5c+32

Subtract 32 from each side

F-32=9/5c+32-32

F-32=9/5c

Multiply each side by 5/9

5/9 (F-32)=5/9*9/5c

5/9 (F-32)=c

4 0
3 years ago
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