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Levart [38]
3 years ago
12

Plz help both problems right answer!!

Mathematics
1 answer:
Aneli [31]3 years ago
7 0
3:5=m:60
m= 36
1. B)36

22in30 min
22+22=44
44in 1hr
44x3=132 in 3hr 
2.  D)132
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It takes 32 hours for a motorboat moving downriver to get from pier A to pier B. The return journey takes 48 hours. How long doe
lina2011 [118]

Answer:

Time taken by the un powered raft to cover this distance is T = 192.12 hr

Step-by-step explanation:

Let speed of boat = u \frac{km}{hr}

Speed of current = v \frac{km}{hr}

Let distance between A & B = 100 km

Time taken in downstream = 32 hours

32 = \frac{100}{u +v}

u + v = \frac{100}{32}

u + v = 3.125 ------ (1)

Time taken in upstream = 48 hours

48 = \frac{100}{u -v}

u -v = \frac{100}{48}

u - v = 2.084 ------- (2)

By solving equation (1) & (2)

u = 2.6045 \frac{km}{hr}

v = 0.5205 \frac{km}{hr}

Now the time taken by the un powered raft to cover this distance

T = \frac{100}{v}

Because un powered raft travel with the speed of the current.

T = \frac{100}{0.5205}

T = 192.12 hr

Therefore the  time taken by the un powered raft to cover this distance is

T = 192.12 hr

3 0
3 years ago
Read 2 more answers
The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
cougar park is shaped like a parallelogram and has an area of 1/16 sqaure mile. Its base is 3/8 mile. What is its height?
nikdorinn [45]
Divide 1/16 by 3/8 and do the rest I got confused
8 0
3 years ago
Read 2 more answers
How did you figure out the answers ? how did you work it out ?
Maksim231197 [3]
How did who figure out what answer?
7 0
3 years ago
Julias text messaging plan costs $8 for the first 400 messages and 20e for each additional text message. If she owes $24.00 for
Makovka662 [10]

Answer:

160 is the answer because 8x20 is 160 also 20÷400 is 20 so that made pretty good sense

4 0
3 years ago
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