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Levart [38]
3 years ago
12

Plz help both problems right answer!!

Mathematics
1 answer:
Aneli [31]3 years ago
7 0
3:5=m:60
m= 36
1. B)36

22in30 min
22+22=44
44in 1hr
44x3=132 in 3hr 
2.  D)132
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Find the difference <br><br><br>-2(c + 2.5) - 5(1.2c + 4)​
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What fraction is equivalent to 36/60 and the sum of the numerator and denominator is 24
almond37 [142]

Answer:

The fraction is \frac{9}{15}

Step-by-step explanation:

\frac{36}{60} = \frac{x}{y}

Where x and y are the numerator and denominator of our new fraction respectively.

Also given is that x + y = 24

So  \frac{x}{y} = 36 ÷ 60 = 0.6

x = 0.6y

Substituting x in x + y = 24 gives;

0.6y + y = 24 , 1.6y = 24

y = 24 ÷ 1.6 = 15

x = 24 - 15 = 9

So our fraction is \frac{9}{15}

5 0
4 years ago
The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

x+y=5600...(1)

y=5600-x...(1)    

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be 40x and cost of y end-zone tickets would be 20y.

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

40x+20y=134000...(2)

Upon substituting equation (1) in equation (2), we will get:

40x+20(5600-x)=134000

40x+112000-20x=134000

20x+112000=134000

20x+112000-112000=134000-112000

20x=22000

\frac{20x}{20}=\frac{22000}{20}

x=1100

Therefore, 1100 field side tickets were sold.

Upon substituting x=1100 in equation (1), we will get:

y=5600-1100

y=4500

Therefore, 4500 end-zone tickets were sold.

3 0
3 years ago
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