
means to say that for any given
, we can find
such that anytime
(i.e. the whenever
is "close enough" to 5), we can guarantee that
(i.e. the value of
is "close enough" to the limit value).
What we want to end up with is

Dividing both sides by 3 gives

which suggests
is a sufficient threshold.
The proof itself is essentially the reverse of this analysis: Let
be given. Then if

and so the limit is 7. QED
Answer:
Answer D
Step-by-step explanation:
The formula is
. We have our r (radius) and h (height), so plugging it all in would give us A = (3.14)(5 + sqrt(12^2)+(5^2). After computing this, you would get answer D, 282.6.
Answer: A cone with height 3 and radius 1
Step-by-step explanation:
Hi, searching I found the image for the question, attached down below.
By rotating the triangle about line m, a cone with height 3 and radius 1 is produced.
Solid 3d objects are produced by rotating a 2d figure around a straight line that lies in the same place.
in our case, if we rotate the triangle around the line, the vertices in touch with the line m remains stationary, while the remaining vertex follows the path of a circle, creating a cone.
Answer:
beam, vault, uneven bars, floor
Step-by-step explanation:
<u><em>The complete question is</em></u>
A group of gymnasts were asked to name their favorite piece of equipment. 0.33 of the gymnasts chose the vault, 4/9 chose the beam, 0.08 chose the floor exercise, and 1/7 chose the uneven parallel bars. List their choices in order of preference from greatest to least.
step 1
Convert 4/9 and 1/7 to decimals in order to compare with the other values
4/9=0.44
1/7=0.14
step 2
Compare the values
0.44 > 0.33 > 0.14 > 0.08
therefore
The order of preferences from greatest to least is
beam, vault, uneven bars, floor
Answer:
7.6 in
Step-by-step explanation:
c = 2πr Divide each side by 2π
r = C/2π Insert values
r = 48/(2×3.14)
r = 48/6.28
r = 7.6 in