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2 years ago

What is the slope and y-intercept -4x+2y=-2

Mathematics

1 answer:

natka813 [3]2 years ago

8 0

Answer:

Slope: 2

Y-intercept: (0, -1) or - 1

Step-by-step explanation:

Given the linear equation, -4x + 2y = -2:

Transform the given equation into its slope-intercept form, y = mx + b:

-4x + 2y = -2

Add 4x to both sides:

-4x + 4x + 2y = 4x - 2

2y = 4x - 2

Divide both sides by 2 to isolate y:

$\frac{2y}{2} = \frac{4x - 2}{2}$

y = 2x - 1 ⇒ This is the slope-intercept form where the slope, m = 2, and the y-intercept is (0, -1).

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2 years ago

What is the answer 4(t)=50t/t^2+25

sveta [45]

Answer:

Step-by-step explanation:

50t/(t^2+25)

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2 years ago

I need help!!!!!!!!!!

Andru [333]

Answer:

Yes

Step-by-step explanation:

The points will be on the same line if they have the same slope. Calculate the slope of each pair. If the slopes are the same, then they lie on the same line.

$m = \frac{y_2-y_1}{x_2-x_1} = \frac{3-2}{1-4} = \frac{1}{-3} = -\frac{1}{3}$

$m = \frac{y_2-y_1}{x_2-x_1} = \frac{4-2}{-2-4} = \frac{2}{-6} = -\frac{1}{3}$

$m = \frac{y_2-y_1}{x_2-x_1} = \frac{4-3}{-2-1} = \frac{1}{-3} = -\frac{1}{3}$

The slope is the same.

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2 years ago

What is the measure of E in degrees

Yakvenalex [24]

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2 years ago

Read 2 more answers

How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

MrRissso [65]

$\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3} \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(3x)^{3 \times \frac{5}{3} }}{(2y^3)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}$

Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

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2 years ago