In order to solve the given expression follow these steps:
1. Take the square roots on both sides in order to get rid of the power on the left side:
√(x-5)² = ±√3
x - 5 = ±√3
2. add 5 on both sides:
x-5 + 5 = 5 ±√3
x = 5 ±√3
Then, the solution is x = 5 ±√3
The data for linear pair are;
The domain are the values (input) on the x-axis which is the time
The range are the values input on the y-axis which is the height reached by the balloon
Part A
The interval of the domain during which the water balloon height is increasing is 0 ≤ x ≤ 2
Part B
The intervals of the domain the water balloon’s height stays the same are;
2 ≤ x ≤ 3 and 6 ≤ x ≤ 8
Part C
The water balloon height is decreasing at the following intervals;
At the interval 3 ≤ x ≤ 4
The rate of decrease = (20 ft. – 80 ft.)/(4 s – 3 s) = -20 ft./s.
At the interval 4 ≤ x ≤ 6
The rate of decrease = (0 ft. – 20 ft.)/(6 s – 4 s) = -10 ft./s
Therefore, the interval of the domain that the balloon’s height is decreasing the fastest is 3 ≤ x ≤ 4
Part D
According to Newton’s law of motion, provided that the no additional force is applied to the the balloon, at 10 seconds, the height of the water balloon is 0 ft. given that the height of the balloon is constantly decreasing from 3 seconds after being thrown off the roof, reaching a height of 0ft. at 6 seconds and maintaining that height up until 8 seconds.
By extending the graph further, the height of 0 ft. is obtained at 10 seconds after the balloon is thrown
is there any graphs that you see in the question? if so put a photo of them so i know what your seeing.
Answer:
m<EBD = 130 degrees
Step-by-step explanation:
We can say that Line EC is bisected by Line AD at point B. The angle CBD = 50 degrees is a supplement of the bisected line EC. With this in mind we can say:
EBD + CBD = 180
And we can solve for EBD:
EBD + CBD = 180
EBD + 50 = 180
EBD = 130
So the measure of angle EBD is 130 degrees.
Cheers.
(a+b)^3 = a^3+b^3+3ab(a+b)
(a+b)^3 = (-1)^3