Answers :
- (A) 18.33%
- (B) 21.65%
- (C) about 173.33
- (D) i really have no way of finding the angles for you, you could try to find them yourself; or maybe just leave it blank?
<h3>
OK, so judging from the bar shown : </h3>
It looks like <u>Rent</u> takes up 1/3 of the space so 33.33..%
It also looks like <u>Loan Repayment</u> + <u>Savings</u> is another 33.33..% but Savings is slightly larger than Loan Repayment so you could just estimate Savings to be 55% and LR to be 45% of the 1/3 space.
LR looks equal to <u>Entertainment</u> making it another <u>14.99.</u>
It also looks like Entertainment + Electricity + Groceries = the last 33.33..%
And since we know <u>Entertainment</u> = 14.99 / 45% of 33.33..
Making <u>Electricity and Water</u> <em>ABOUT</em> 35% of 33.33... which is <u>11.66</u>
And Groceries is somehow 20% of 33.33 = <u>6.66</u>
- Rent = 33.33..%
- Savings = 18.33%
- Loan Repayment 14.99%
- Entertainment 14.99%
- Electricity and Water 11.66%
- Groceries = 6.66%
<h3>
All of these added together equal <u><em>
ABOUT</em></u>
100%</h3>
To solve this, we use the z-test.
z = (x – u) / σ
when x = 450
z = (450 – 550) / 100
z = -1
We use the standard distribution tables to find for P.
P = 0.1587
Since we are looking for values greater than x = 450,
therefore:
1 – 0.1587 = 0.8413
This means that 84.13% have bladder volume larger than 450
mL.
The answer is "A'B'C'D' is obtained by rotating ABCD counterclockwise 90degrees about the origin and then reflecting it over the x-axis"
I got the answer by trying out each option, since none of the first three gave me result expected, I knew it was the fourth one.
