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alukav5142 [94]
3 years ago
12

Write an inequality for the graph

Mathematics
2 answers:
Liula [17]3 years ago
8 0
Answer is d
yup
yup yup
Montano1993 [528]3 years ago
6 0
It is d you are right because open circle mean <or> and it was pointing to the right so that means it was x>3

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Make t the subject of the formula q=2-4t/t+3
stira [4]

Answer:

q. (3+t)=2-4t

q.3+q.t=2-4t

4t+q.t=2-3q

t (4+q)=2-3q

t=2-3q/4+q

Step-by-step explanation:

PLZZ MARK AS BRAINLIEST!!!!!

8 0
2 years ago
What is the value of s?3/8 (s 9 ) = −19?
denpristay [2]
S=<span>−<span>1.546727
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3 years ago
Which of the options below does the month-end review process help with? Select all that apply.
Shkiper50 [21]

The month-end review process help with the following below:

  • Finding transactions with outstanding issues.
  • Dealing with unreconciled accounts.
  • Running payroll.
  • Identifying discrepancies with accounts and starting balances.

<h3>What is Month-end review process?</h3>

This is usually done by the accounting department of an organization and are involved in payrolling.

Outstanding transactions and accounts are also reviewed so as to ensure accuracy.

Read more about Month-end review process here brainly.com/question/24134045

#SPJ1

4 0
1 year ago
Read 2 more answers
There are 10 boys trying out for the track team. Truman and Ryan are the two fastest runners. If the coach randomly picks two bo
vichka [17]
10 kids total

picking Truman would be 1 out of 10 or 1/10

then there would be 9 kids left so picking Ryan would be 1 out of 9 or 1/9

the probability of picking both would be 1/10 * 1/9 = 1/90
5 0
3 years ago
In a recent Super Bowl, a TV network predicted that 50 % of the audience would express an interest in seeing one of its forthcom
coldgirl [10]

Answer:

z= -0.968

We can conclude that we fail to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that  they would watch one of the television shows not differs from 0.5 or 50% .  

Step-by-step explanation:

1) Data given and notation n  

n=106 represent the random sample taken

X=48 represent the people who says that  they would watch one of the television shows.

\hat p=\frac{48}{106}=0.453 estimated proportion of people who says that  they would watch one of the television shows.

p_o=0.5 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that 50% of people who says that  they would watch one of the television shows.:  

Null hypothesis:p=0.5  

Alternative hypothesis:p \neq 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.453 -0.5}{\sqrt{\frac{0.5(1-0.5)}{106}}}=-0.968  

4) Statistical decision  

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level is not provided, but we can assume \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(z  

So based on the p value obtained and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we fail to reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that  they would watch one of the television shows not differs from 0.5 or 50% .  

6 0
3 years ago
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