The answer is b hopefully I helped
The answer is 540 m2 hope this helps
Answer:
The domain of function 
is set of all real numbers.
Domain: (-∞,∞)
Step-by-step explanation:
Given:
the domain of both the above functions is all real number.
To find domain of :
Substituting functions 
and 
to find
The product can be written as difference of squares. ![[a^2-b^2=(a+b)(a-b)]](https://tex.z-dn.net/?f=%5Ba%5E2-b%5E2%3D%28a%2Bb%29%28a-b%29%5D)
∴ 
The degree of the function is 2 as the exponent of leading term 
is 2. Thus its a quadratic equation.
For any quadratic equation the domain is set of all real numbers.
So Domain of is (-∞,∞)
Hey There!
If i got this down right,
An = A1 + (n - 1)d
Sn = A1 + A2 + A3 + ... + An
A1 is given by
Sn = n (A1 + An) / 2
For Example
An = A1 + (n - 1)d
= 6 + 3 (n - 1)
= 3 n + 3
n = 50
Hope This Helps!!!
<u>Answer</u>:
-3 is an integer, rational number and real number , so correct option id D) that is all of the above.
<u>Explanation:</u>
Integer is all natural number that a 1 , 2 , 3 , 4 ……. And zero and negative of natural numbers like -1 , -2 , -3 , - 4 ……. So -3 is an integer.
Rational number is the number which can be represented in the form of p/q where p and q are integers and q ≠ 0 . As -3 can be represented as (-3)/1 . hence -3 is also a rational number.
Real number is all number which can be represented on number line. All integers and rational numbers are real numbers . so -3 is also a real number.
Hence as -3 is an integer, rational number and real number , so correct option id D) that is all of the above.
