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Nat2105 [25]
3 years ago
14

2x^4–5x^3+x^2+3x+2=? X=5

Mathematics
1 answer:
DanielleElmas [232]3 years ago
3 0

Answer:

2x^4–5x^3+x^2+3x+2=

2 \times 5^4–5 \times 5^3+5^2+3 \times 5+2

= 2 × 625 – 5 × 125 + 25 + 3 × 5 + 2

=1250 – 625 + 25 + 15 +2

= 1292 – 625

= 667

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For circle O, mCD=125° and m
Burka [1]

CA is a diameter of the circle, so m\widehat{AC}=180^\circ, which means m\angle AOB=m\angle AOD=m\widehat{AD}=180^\circ-m\widehat{CD}=55^\circ. Then m\boxed{\angle ABO}=90^\circ-55^\circ=35^\circ.

This means m\angle CBO=55^\circ-35^\circ=20^\circ. Also, if m\angle AOB=55^\circ, then m\angle BOC=180^\circ-55^\circ=125^\circ, which in turns tells us that m\boxed{\angle BCO}=180^\circ-20^\circ-125^\circ=35^\circ.

3 0
3 years ago
Last month Marybeth was charged $112for a 945kWh of electricity. How much did the company charger her per kWh, to the nearest ce
Usimov [2.4K]
She was charged 12 cents per kWh
3 0
3 years ago
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9 – 2k = 25 what is k
worty [1.4K]

Answer:

k = - 8

Step-by-step explanation:

Subtract 9 from both sides to get the constants on one side and the variables on the other

9 - 2k = 25

- 2k = 25 - 9

Simplify

- 2k = 16

Divide by -2 on both sides to isolate the variable, then simplify once more.

- 2k/ -2 = 16/ -2

k = 16/ -2

k = -8

8 0
3 years ago
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Solve for y:<br> x + 2y = -8<br><br> y=-1/2x+4<br> y=-1/2x-4<br> y=-2x - 4<br> y=1/2x-4
adelina 88 [10]

Answer:

x + 2y = -8 = y = -4 - 1/2x

y= -1/2x + 4 =  y = 4

y= -1/2x - 4 = y = -4

y=-2x - 4 = y = -4

y=1/2x-4 = y = -4

Step-by-step explanation:

(x + 2y = -8 = y = -4 - 1/2x)

x+2y=-8\\2y=-8-x\\y=-4-\frac{1}{2}x\\

4 0
3 years ago
What is the product?
fredd [130]

Answer:

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}   =  \frac{2}{k + 2}

Step-by-step explanation:

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}

To solve the above, we need to follow the steps below;

4k+2 can be factorize, so that;

4k +2 = 2 (2k + 1)

k² - 4  can also be be expanded, so that;

k² - 4 = (k-2)(k+2)

Lets replace  4k +2  by  2 (2k + 1)

and

k² - 4 by  (k-2)(k+2)   in the expression  given

\frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}

\frac{2(2k+ 1)}{(k-2)(k+2)}   ×  \frac{k-2}{2k+1}

(2k+1) at the numerator will cancel-out (2k+1) at the denominator, also (k-2) at the numerator will cancel-out (k-2) at the denominator,

So our expression becomes;  

\frac{2}{k + 2}

Therefore, \frac{4k + 2}{k^{2}-4 }  ×  \frac{k-2}{2k+1}   =  \frac{2}{k + 2}

3 0
3 years ago
Read 2 more answers
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