2 years ago

Driving 3 miles turn right drive 4 miles what is your straight line distance from your starting point

1 answer:

5 0

5 miles

You can use the special right triangles for this equation. Since the side lengths are 3 and 4, the hypotenuse of the triangle would be 5, or you can use the equation a2 + b2 = c2, 3^2 + 4^2 = c2, 25 = c2, c=5

You might be interested in

Use proportions to solve each of the problems below. Homework Help ✎

Yakvenalex [24]

Answer:

Question 2:

45 pages 700 pages

-------------- = -------------

1 hour X hours

1 x 700= 700

700/ 45= 15 and 5/9

15 and 5/9 hours

Question 3:

$\frac{250}{3} \\$ = 88.33 lbs

7 0

2 years ago

1. To the nearest ten and the nearest hundred, a store sold about 300 puzzles.

BartSMP [9]

Answer:

B. 279

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Shreya's Bikes rents bikes for $15 plus $4

Nady [450]

Answer:

A, 8

Step-by-step explanation:

Use the equation 15+4x=47

Subtract 15 from both sides to get

4x=32

divide to get 8

x=8

3 0

3 years ago

1.What are the coordinates of the vertices of ABC? Use the coordinates to find the lengths of AC and AB .

Andrew [12]

Answer/Step-by-step explanation:

✔️Coordinates of vertices ABC:

A(2, 2)

B(6, 2)

C(2, -1)

✔️AC = |2 - (-1)| = 3 units

AB = |2 - 6| = 4 units

2. Distance formula => $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Distance between B(6, 2) and C(2, -1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Where,

$B(6, 2) = (x_1, y_1)$

$C(2, -1) = (x_2, y_2)$

$BC = \sqrt{(2 - 6)^2 + (-1 - 2)^2}$

$BC = \sqrt{(-4)^2 + (-3)^2}$

$BC = \sqrt{16 + 9} = \sqrt{25}$

$BC = 5 units$

7 0

2 years ago

Consider the original parallelogram and the reduction.

IgorLugansk [536]

I can confirm that it is A as I took the test and got 100%.

7 0

2 years ago

Read 2 more answers