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asambeis [7]
2 years ago
14

Driving 3 miles turn right drive 4 miles what is your straight line distance from your starting point

Mathematics
1 answer:
Flura [38]2 years ago
5 0

5 miles

You can use the special right triangles for this equation. Since the side lengths are 3 and 4, the hypotenuse of the triangle would be 5, or you can use the equation a2 + b2 = c2, 3^2 + 4^2 =  c2, 25 = c2, c=5

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Use proportions to solve each of the problems below. Homework Help ✎
Yakvenalex [24]

Answer:

Question 2:

45 pages 700 pages  

-------------- = -------------  

1 hour X hours  

1 x 700= 700  

700/ 45= 15 and 5/9  

15 and 5/9 hours  

Question 3:

\frac{250}{3} \\ = 88.33 lbs

7 0
2 years ago
1. To the nearest ten and the nearest hundred, a store sold about 300 puzzles.
BartSMP [9]

Answer:

B. 279

Step-by-step explanation:

5 0
3 years ago
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Shreya's Bikes rents bikes for $15 plus $4
Nady [450]

Answer:

A, 8

Step-by-step explanation:

Use the equation 15+4x=47

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3 0
3 years ago
1.What are the coordinates of the vertices of ABC? Use the coordinates to find the lengths of AC and AB .
Andrew [12]

Answer/Step-by-step explanation:

1.

✔️Coordinates of vertices ABC:

A(2, 2)

B(6, 2)

C(2, -1)

✔️AC = |2 - (-1)| = 3 units

AB = |2 - 6| = 4 units

2. Distance formula => d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Distance between B(6, 2) and C(2, -1):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Where,

B(6, 2) = (x_1, y_1)

C(2, -1) = (x_2, y_2)

BC = \sqrt{(2 - 6)^2 + (-1 - 2)^2}

BC = \sqrt{(-4)^2 + (-3)^2}

BC = \sqrt{16 + 9} = \sqrt{25}

BC = 5 units

7 0
3 years ago
Consider the original parallelogram and the reduction.
IgorLugansk [536]

I can confirm that it is A as I took the test and got 100%.

7 0
2 years ago
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