Help me please its super easy
2 answers:
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If you mean that you can only use each number along the four expressions, it looks impossible to me. Here's the proof.
Multiplications and divisions are the most restrictive operations, because only some triplets will work. In particular, you can choose
I'm listing them in triplets because you can use them in many ways. For example, the first triple can be used to generate
But it doesn't really matter, in all cases you used numbers 2,3, and 6.
If you look closely, all triplets but the last one involve 2. This means that we must use the last one, because otherwise we would use two triplets with two, and we would have repetitions.
So, we surely have to use (3,4,12), either to write or
.
This means that we can't use 3, 4 and 12 anymore. The only triplet remaining is (2,5,10).
For example, let's say that our multiplication is and our division is
.
We're left with the following numbers:
From here, we're left with a few choices for the addition: if we choose we're left with 8,9 and 11. We can't write any subtraction with these numbers.
If we choose , we're left with 6, 9 and 11. We can't write any subtraction with these numbers.
If we choose , we're left with 6, 7 and 11. We can't write any subtraction with these numbers.
To recap, we're forced to use 2,3,4,5,10 and 12 for the multiplication and the division, and the remaining numbers don't allow to write an addiction and a subtraction.
Thus, you can't use all the operations involving numbers 1-12 only once.
Answer:
The domain is all real numbers. The range is {y|y ≤ 16}
Step-by-step explanation:
we have
This is a the equation of a vertical parabola open downward
The vertex is a maximum
The vertex is the point (-1,16)
see the attached figure
therefore
The domain of the function is all real numbers ----> interval (-∞,∞)
Te range of the function is
All real numbers less than or equal to 16 ----> interval (-∞,16]
