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katrin [286]
3 years ago
13

What is the ratio of total shapes to triangles? Circle ⭕ triangle triangle circle ⭕ triangle triangle circle ⭕ triangle triangle

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
6 0
3:2. There's a total of 9 shapes, 6 triangles, and 3 circles. 
Next, you take the ratio of 9:6 and divide each number by 3, one at a time.
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PLEASE HELP I cannot get this wrong WILL MARK BRAINLIEST
Nana76 [90]

The answer is graph number 2

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What is the length of segment AE?
DedPeter [7]
By looking at the bottom length of both triangles, we can determine the scale from one to the other.

C-E = 30 units
D-F = 28 units

This can be translated as the fraction 15/14.

So if we look back at the possible answers, both B and C are likely candidates for being the answer.

But to get the answer, we multiply 24 X (15/14).

Which is 25.7, or 25 and 5/7.  Your answer is C.
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Prime factorization of 92
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3 0
3 years ago
Read 2 more answers
According to the rational root theorem, what are all the potential rational roots of f(x)=5x^3-7x+11
Genrish500 [490]

Answer:

\pm11,\pm1,\pm\frac{11}{5},\pm\frac{1}{5}

Step-by-step explanation:

The given polynomial function is

f(x)=5x^3-7x+11

According to the Rational Roots Theorem, the ratio of all factors of the constant term expressed over the factors of the leading coefficient.

The potential rational roots are

\pm\frac{11}{1}=\pm11

\pm\frac{1}{1}=\pm1

\pm\frac{11}{5}

\pm\frac{1}{5}

4 0
3 years ago
The average weight of the class of 35 students was 45 KG. with the admission of a new student the average weight came down to 44
melamori03 [73]

The weight of the new student is 27 kg.

Average weight

= total weight ÷total number of students

<h3>1) Define variables</h3>

Let the total weight of the 35 students be y kg and the weight of the new student be x kg.

<h3>2) Find the total weight of the 35 students</h3>

<u>45 =  \frac{y}{35}</u>

y= 35(45)

y= 1575 kg

<h3>3) Write an expression for average weight of students after the addition of the new student</h3>

New total number of students

= 35 +1

= 36

Total weight

= total weight of 35 students +weight of new students

= y +x

44.5  =  \frac{y + x}{36}

<h3>4) Substitute the value of y</h3>

44.5 =  \frac{1575 + x}{36}

<h3>5) Solve for x</h3>

36(44.5)= 1575 +x

1602= x +1575

<em>Subtract 1575 from both sides:</em>

x= 1602 -1575

x= 27

Thus, the weight of the new student is 27 kg.

7 0
3 years ago
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