The probability that the aircraft is overloaded is 97.98%, which means the pilot should take the action.
In a Normal distribution with mean ц and standard deviation σ, the z-score of a measure x is given by:
Z = X-ц / σ
· It measures how many standard deviations the measure is from the mean.
· After finding Z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
· By the Central Limit Theorem, the sampling distribution of sample means of the size n has standard deviation σ
σ = σ /
σ is standard deviation
n is the sample size.
Given that the mean and the standard deviation of the population is 176.1 lb and 35.4 respectively.
⇒ ц = 176.1 and σ = 35.4
For a sample of 43 passengers, we have
n = 43
σ = 
σ = 5.398
Z = X-ц / σ
Z = 
Z = -2.05 has p- value of 0.9798
The probability that the aircraft is loaded is
1 - p-value of Z
1 - 0.0202 = 0.9798
The probability that the aircraft is overloaded is 97.98%
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For this case, the first thing we must do is define a variable.
We have then:
x: number of muffin plates
We now write the expression that models the problem.
We know there are 4 muffins in each dish, therefore, we have:

Substituting for x = 0 we have:
Answer:
There are 0 lemon muffins
d: 0
Answer: He still has to mow 45 lawns, or 75% of the lawns before he is finished.
264/2200 = 0.12
0.12*100 = 12%