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3 years ago

of the 80 guests invited to a wedding, 28 attended the wedding. What percent of the invited guests attended the wedding?

Mathematics

1 answer:

klasskru [66]3 years ago

4 0

Answer:

35%

Step-by-step explanation:

% of guests who attended the wedding is number of guests who attended the wedding divided by the number of invited guests and the result multiplied by 100%

Therefore

28/80 x 100%

0.35 x 100%

35%

35% of the invited guests attended the wedding

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Find the value of a in parallelogram PQRS.

svetlana [45]

360=(4a-12)+(12a)+(3a)+(x)
A=18.6 or 93/5

6 0

3 years ago

The quality-control manager at a compact fluorescent light bulb (CFL) factory needs to determine whether the mean life of a la

Illusion [34]

Answer:

a) Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 7539

b) $t=\frac{7359-7539}{\frac{840}{\sqrt{49}}}=-1.5$

The degrees of freedom are given by:

$df=n-1=49-1=48$

The p value is given by:

$p_v =P(t_{(48)}$

c) $7359-2.01\frac{840}{\sqrt{49}}=7117.8$

$7359+2.01\frac{840}{\sqrt{49}}=7600.2$

d) For this case since the confidence interval contains the value of 7539 we don't have enough evidence to reject the null hypothesis at the significance level given of 5%. same conclusion using the hypothesis test and with the confidence interval

Step-by-step explanation:

Part a and b

Data given

$\bar X=7359$ represent the sample mean

$\sigma=840$ represent the population standard deviation

$n=49$ sample size

$\mu_o =7539$ represent the value to test

t would represent the statistic

$p_v$ represent the p value

Hypothesis to verify

We want to verify if the mean life is different from 7539 hours, the system of hypothesis would be:

Null hypothesis: $\mu \geq 7539$

Alternative hypothesis: $\mu < 7539$

The statistic for this case would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{7359-7539}{\frac{840}{\sqrt{49}}}=-1.5$

The degrees of freedom are given by:

$df=n-1=49-1=48$

The p value is given by:

$p_v =P(t_{(48)}$

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different from 7539

Part c

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

We can find the critical value using the confidence level given of 95% and using the t distribution with 48 degrees of freedom we got $t_{\alpha/2}=\pm 2.01$

Now we have everything in order to replace into formula (1):

$7359-2.01\frac{840}{\sqrt{49}}=7117.8$

$7359+2.01\frac{840}{\sqrt{49}}=7600.2$

Part d

For this case since the confidence interval contains the value of 7539 we don't have enough evidence to reject the null hypothesis at the significance level given of 5%. same conclusion using the hypothesis test and with the confidence interval

3 0

3 years ago

A grasshopper jumps from the ground. The path of the grasshopper is modeled by the equation y=−0.5x2+8x where x is the horizonta

Marysya12 [62]

Please use " ^ " to indicate exponentiation: <span>y=−0.5x^2+8x

Examining this function, we see that its graph is a vertical parabola opening down.

You did not supply instructions for this problem.
However, one could guess that you might want to find the highest point of the grasshopper's path. To do this, find the vertex: Find the x value defined by

x = -b/(2a). Here, a= -0.5 and b= 8. Thus, the vertex is at x = -8/(2[-0.5]), or

x -8/(-1) = 8 units. The corresponding y value is then

y = </span><span>−0.5*8^2+8(8) = -0.5(64) + 64, or 32 units.</span>

6 0

3 years ago

PLZ IN DESPERATE NEED OF HELP!!!!!

tester [92]

The answer would be 4+y=-36

8 0

3 years ago

In the state of Pennsylvania, each standard automobile license plate number consists of three letters followed by a four-digit n

Ann [662]

Answer:

17,576,000

Step-by-step explanation:

From A to Z, there are 26 possible letter characters (L).

From 0 to 9, there are 10 possible numeric characters (N)

If each standard automobile license plate number in Pennsylvania follows the pattern LLLNNNN, the number of license plates that can be formed is:

$n=26*26*26*10*10*10*10\\n=17,576,000$

17,576,000 distinct license plate numbers can be formed in Pennsylvania.

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4 years ago