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2 years ago

Graph the line with y intercept -1 and -4 slope . Brainiest ASAP

Mathematics

1 answer:

Jobisdone [24]2 years ago

6 0

Graph the line with y-intercept at -1 and slope that's -4?

$y=mx+b$ where m is the slope and b is the y-intercept.

So clearly, the answer is $y=-4x-1$

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Identify the polynomial.

Alexxandr [17]

Answer:

it's a trinomial

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2 years ago

129931 Rounded to the nearest thousand

maks197457 [2]

13,000.......................hope it helps!

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3 years ago

Need help please would really be greatful

Rainbow [258]

Answer:

122°

Step-by-step explanation:

The formula for finding the sum of all angles in a polygon is:

(n-2) * 180°

n is the number of angles

Here n = 7, so the sum of all angles is

(7-2) * 180° = 900°

x = 900 - 128 - 130 - 120 - 115 - 145 - 140 = 122°

Make me the brainliest ;)

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2 years ago

Write the equation for a 3rd degree polynomial function that has roots at x = 1–3i and x = 2. The y‑intercept is (0,10). Write a

HACTEHA [7]

Answer:

$\displaystyle P(x)=-\frac{1}{2}(x^2+2x+10)(x-2)$

Step-by-step explanation:

<u>Factored Form Of Polynomials </u>

If we know the roots of a polynomial as

$\alpha _1,\alpha _2,\alpha _3$

the polynomial can be expressed in factored form as

$a(x-\alpha _1)(x-\alpha _2)(x-\alpha _3)$

We are given two of the three roots of the polynomial:

$\alpha _1=1-3i$

$\alpha _2=2$

The other root must be the conjugate of the complex root:

$\alpha _3=1+3i$

Recall the product of two complex conjugate numbers is

$(1-3i)(1+3i)=1^2-(3i)^2=1+9=10$

The required polynomial is

$P(x)=a\left[ x-(1-3i)\right ]\left[ x-(1+3i)\right ](x-2)$

$P(x)=a(x^2+2x+10)(x-2)$

This is the factored form of the polynomial where only real numbers appear

We need to find the value of a, such as

$P(0)=10$

$P(0)=a(0^2+2(0)+10)(0-2)=10$

$-20a=10$

Thus the value of a is

$\displaystyle a=-\frac{1}{2}$

The expression of the required polynomial is

$\boxed{P(x)=-\frac{1}{2}(x^2+2x+10)(x-2)}$

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2 years ago

Help please ?!?!?!!???????!???!???!!????!!??!??!?!?!!??!?!!????

wariber [46]

No association because it’s scattered

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2 years ago