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lawyer [7]
3 years ago
5

??????? Help please please

Mathematics
1 answer:
Alborosie3 years ago
6 0
I am pretty sure you can only make one.
 If two sides are known, and one of the angles, then the other bits can be deduced and are fixed.
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Math 2 help ummmmmyeah
Kipish [7]

Answer:

1. 38 degrees

2. 38 degrees

Step-by-step explanation:

It tells you that angle 1 is 38 degrees, and they are supplementary angles, which means angle 2 is also 38 degrees.

Hope this helps :)

Let me know if there is anything to fix!!

7 0
3 years ago
Review the diagram of a locket in the shape of an ellipse.
Helen [10]

Answer:

B

Step-by-step explanation:

If you graph y^2/361 + x^2/169=1 you will get the same graph depicted in the equation.

8 0
3 years ago
Read 2 more answers
Solve 25 = 5x − 4.<br><br> one half<br> 2<br> 4<br> 6
swat32

Answer:

29/5 =x

Step-by-step explanation:

25 = 5x − 4

Add 4 to each side

25+4 = 5x − 4+4

29 = 5x

Divide each side by 5

29/5 = 5x/5

29/5 =x

3 0
3 years ago
Which equation can be used to find T the number of tickets each class needs to sell so that the total amount raised is the same
sasho [114]

Answer:

C.

Step-by-step explanation:

If you know how much each class is selling tickets for and how much they've already raised then you take those two values and set them equal to each other.

<em>2.5t + 350 = 3t + 225</em>

To actually find the number of tickets each class would have to sell you would just solve for t.

5 0
3 years ago
The probability that Sandra gets a ride to work on any morning is 0.7. The probability that she gets a ride 3 times in a 5-day w
guajiro [1.7K]

Answer: The probability that she gets a ride 3 times in a 5-day work week is <u>0.31</u>.

The probability that she gets a ride at least 2 times in a 5-day workweek is <u>0.97</u>.

Step-by-step explanation:

By binomial distribution formula:

P[X=r]=^nC_rp^rq^{n-r} , where n is the number of trials , r is the number of success, p is the probability of success and q is the probability of failure.

Given : n=5

p = 0.7

q= 1-0.7=0.3

Now, the probability that she gets a ride 3 times in a 5-day work week :

P[X=3]=^5C_3(0.7)^3(0.3)^{5-3}\\\\=10(0.7)^3(0.3)^2=0.3087\approx0.31

The probability that she gets a ride at least 2 times in a 5-day workweek :

P[X\geq2]=1-P[X

5 0
3 years ago
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