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3 years ago

What is for F(x) = 2x

Mathematics

1 answer:

Contact [7]3 years ago

8 0

If you mean wheat the function of 2x is, then it is 2.

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Find NL. Not sure to to solve this.

Paul [167]

Answer:

NL= 2 × HI

x+24 =2 × (X+16)

x+24=2x + 32

2x-x= 24-32

x= – 8

NL=x+24 = –8 +24= 16

So ; NL= 16

I hope I helped you^_^

4 0

3 years ago

Read 2 more answers

Someone please help me on this!

Alexxx [7]

Answer & Step-by-step explanation:

This can be proven with the SAS theorem (side-angle-side)

With a perpendicular bisector, the line it bisects is cut directly in half. This creates two equal sides:

$GJ=IJ$

and it creates two 90° angles:

∠ $GJH=$ ∠ $IJH$

And because of the reflexive property of congruence:

$JH=JH$

Side-Angle-Side.

:Done

6 0

3 years ago

Subtract. (−9.6x+7)−(7.3x−9) Enter your answer, in simplified form, in the box.Can somebody help me with this equation?

ZanzabumX [31]

-16.9x + 16 is the correct answer. You have to remove the parentheses, collect the like terms, and then simplify.

8 0

3 years ago

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The parabola x = y² - 9 opens:

irinina [24]

This is what it looks like. It opens to the right.

8 0

4 years ago

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Test the series for convergence or divergence (using ratio test)

Triss [41]

Answer:

$\lim_{n \to \infty} U_n =0$

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

Step(i):-

Given series is an alternating series

∑ $(-1)^{n} \frac{n^{2} }{n^{3}+3 }$

Let $U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }$

By using Leibnitz's rule

$U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }$

$U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}$

Uₙ-Uₙ₋₁ <0

Step(ii):-

$\lim_{n \to \infty} U_n = \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }$

$= \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }$

= $= \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }$

$=\frac{1}{infinite }$

$\lim_{n \to \infty} U_n =0$

∴ Given series is converges

3 0

3 years ago