What is the value of tan-1(100/41)

Which of the following statement(s) describes the rate of change of f over the interval 1.5 ≤ x ≤ 3? Select all that apply.

Vesnalui [34]

2 Answers: Choice B and Choice C

The rate of change is 2.

The rate of change is constant.

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Explanation:

The first point on the left is when x = 1.5 and it has a height of y = 1

The point (1.5, 1) is on the line.

So is the point (3,4) for similar reasoning.

Compute the slope between those points

m = (y2-y1)/(x2-x1)

m = (4-1)/(3-1.5)

m = 3/(1.5)

m = 2

The slope is 2, which is the same as saying the rate of change is 2. This only applies when x > 1 of which the interval 1.5 ≤ x ≤ 3 is a part of.

Since the slope stays at 2 on the interval 1.5 ≤ x ≤ 3, this means we consider the slope to be constant. If the curve bended at all on this interval, then it wouldn't be a constant slope.

6 0

1 year ago

K anyone help please

tigry1 [53]

Answer:

Step-by-step explanation:

Given equation is,

a). y = $\frac{6}{x}$

x 0.5 1 2 3 4 5 6

y $\frac{6}{0.5}=12$ $\frac{6}{1}=6$ $\frac{6}{2}=3$ $\frac{6}{3}=2$ $\frac{6}{4}=1.5$ $\frac{6}{5}=1.2$ $\frac{6}{6}=1$

b). By plotting the input-output values on the graph we get the curve as shown in option C.

Therefore, Option C will be the answer.

7 0

3 years ago

The ages of five friends are 25, 36, 33, 36 and 30 how many of friends are older than the average (arithmetic mean) age?

Murrr4er [49]

Answer:

3 friends are older than the average.

Step-by-step explanation:

First find the mean. The mean can be found adding all the numbers in the set together and dividing by the amount of numbers in the giving set:

(25 + 36 + 33 + 36 + 30)/5 = (160)/5 = 32

The average age is 32. There are 3 friends that are older than the average (33 , 36 , 36, respectfully).

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4 0

1 year ago

How to solve 6x-3=7x-11

VladimirAG [237]

Hello there.

How to solve 6x-3=7x-11
6x−3=7x−11
6x−3−7x=7x−11−7x−x−3=−11
−x−3+3=−11+3−x=−8
−x/−1=−8/−1x=8
Answer: 8

6 0

3 years ago

Cassie has test grades of 62, 85 and 89 on the first three tests in herpre-algebra class. What are the possible scores she can m

Vsevolod [243]

Explanation:

The test grade for 1st three tests = 62, 85, 89

Let the fourth test score = x

The result we hoping to get is grade B.

Let's find the average of the four test score

$\text{Average = }\frac{Su\text{ m of all test score}}{nu\text{mber of test score}}$ $\begin{gathered} s\text{ um of test scores = 62 + 85 + 89 + x} \\ nu\text{mber of test score = 4} \\ \frac{\text{62 + 85 + 89 + x}}{4}=\text{ Average} \end{gathered}$ $\begin{gathered} A\text{ grade B represents atleast 80} \\ \text{Atleast represents }\ge \\ \frac{\text{62 + 85 + 89 + x}}{4}\text{ }\ge\text{ 80} \\ \frac{\text{236 + x}}{4}\text{ }\ge\text{ 80} \end{gathered}$ $\begin{gathered} \text{236 + x }\ge\text{ }80(4) \\ \text{236 + x }\ge\text{ }320 \\ \text{subtract }236\text{ from both sides:} \\ 236\text{ - 236 + x }\ge\text{ }320\text{ - 23}6 \\ x\text{ }\ge\text{ 84} \end{gathered}$

This means Cassie needs to score 84 or more to get a grade of B

In ineq

3 0

1 year ago