$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{0}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{0}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{0}}}\implies -\cfrac{1}{3}$

5 0

3 years ago

Eleven members of the Middle School Math Club each paid the same amount for a guest speaker to talk about problem solving at the

Ilia_Sergeevich [38]

The correct answer for the question that is being presented above is this one: "The missing digit is 3."

The missing digit is represented by A ⇒ $1A2, where A represents a whole number from 0 to 9.

Try substituting any number from 0 to 9 for A (the middle digit or tens place) , then divide by 11 members.

Option 2: A = 3 ⇒ $1 3 2
$ 132 ÷ 11 = $12

The only one-digit that gives a whole number quotient when it takes the place of tens digit in $1 __2 is 3. Because $ 132 ÷ 11 = $ 12. (Option 2)

The missing digit is 3.

6 0

3 years ago

A polynomial p has zeros when x = 5, x = -1, and x = -1/4

mafiozo [28]

Answer:

$x=5$ ⇒ $(x-5)=0$